Answer:
4448 feet²
Step-by-step explanation:
Using the formula 
we can take the length, width and height and plug them in. 
, solving this equation we get 
.
Answer:
Graph B
Step-by-step explanation:
The solutions to a quadratic equation are the points on which we have the graph of the curve touching the x-axis
Now the first thing we will do here is to solve the quadratic equation graph;
x^2 + 4x -12 = 0
x^2 +6x - 2x -12 = 0
x (x + 6) -2(x + 6) = 0
(x-2)(x + 6) = 0
x = 2 or -6
So the graph that touches the x-axis at the points x = 2 and x = -6 is the solution to the quadratic equation
Graph B is the closest to what we have as answer
The graph of f(x) + 1 is the graph in the option C.
<h3>
Which is the graph of f(x) + 1?</h3>
For a given function f(x), a vertical translation is written as:
g(x) = f(x) + N
- If N > 0, then the translation is upwards.
- If N < 0, then the translation is downwards.
Here we have g(x) = f(x) + 1, so we have a translation of 1 unit upwards, the graph of f(x) + 1 is the graph of f(x) but translated one unit upwards.
From that, we conclude that the correct option is C.
If you want to learn more about translations:
brainly.com/question/24850937
#SPJ1
Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
