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2 years ago

Can someone help me with this

Mathematics

1 answer:

just olya [345]2 years ago

7 0

Step-by-step explanation:

these are composite functions : a function of a function of a value.

this can have many more "staging" levels.

in essence, we calculate the functional result of the innermost function (with the given value) first, use that functional result as input value for the next function to the left. use that functional result as input value for the next function to the left. ...

f(g(x)) means therefore we start with g(x).

g(f(x)) means we start with f(x).

that is all. it is really simple. and actuality fun (like a maze - remember e.g. computer games, where you walked through one door and excited through a totally different door ?).

f(g(0)) =

so, we need g(0) = 4 - 0² = 4

and now we calculate

f(4) = 7×4 + 6 = 28 + 6 = 34

therefore,

f(g(0) = 34

g(f(0)) =

so, we need f(0) = 7×0 + 6 = 6

and now we calculate

g(6) = 4 - 6² = 4 - 36 = -32

therefore,

g(f(0)) = -32

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3 years ago

What is 1/2 2/3 1/4 and 5/6 in least to greatest

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3 years ago

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Perform the indicated operation and express the result as a simplified complex number. I need help with 35

skelet666 [1.2K]

Given:-

$\frac{3+4i}{2-i}$

To find:-

The simplified form.

At first we take conjucate and multiply below and above.

The conjucate is,

$2+i$

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$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}$

Now we simplify. so we get,

$\frac{3+4i}{2-i}\times\frac{2+i}{2+i}=\frac{6+3i+8i+4(i)^2}{2^2-i^2}$

We know the value of,

$i^2=-1$

Substituting the value -1. we get,

$\begin{gathered} \frac{6+3i+8i+4(i)^2}{2^2-i^2}=\frac{6+3i+8i+4(-1)_{}^{}}{2^2-(-1)^{}} \\ \text{ =}\frac{6-4+11i}{2+1} \\ \text{ =}\frac{2+11i}{3} \end{gathered}$

So now we split the term to bring it into the form a+ib. so we get,

$\frac{2+11i}{3}=\frac{2}{3}+i\frac{11}{3}$

So the required solution is,

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3 0

1 year ago

I'm really not sure how to go about solving this algebraic equation, please help! .513 = (2x)^2 / (.05-x)

LiRa [457]

Let's set it up like this:
$0.513=\frac{\left(2x\right)^2}{\left(0.05-x\right)}$
Multiply both sides by $0.05-x$
$0.513\left(0.05-x\right)=\frac{\left(2x\right)^2}{0.05-x}\left(0.05-x\right)$
$0.513\left(0.05-x\right)=4x^2$
We are then going to use the distributive property. Since we also know that the opposite of an number that is squared is the square root, we can also apply that. We would be left with something like this:
$x=-\frac{0.513+\sqrt{0.673569}}{8},\:x=\frac{\sqrt{0.673569}-0.513}{8}$
The variable $x$ can be both positive or negative.
We have found successfully our answer.

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish<span />

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3 years ago