Question

I'm really not sure how to go about solving this algebraic equation, please help! .513 = (2x)^2 / (.05-x)

Answer 1

Let's set it up like this:
$0.513=\frac{\left(2x\right)^2}{\left(0.05-x\right)}$
Multiply both sides by $0.05-x$
$0.513\left(0.05-x\right)=\frac{\left(2x\right)^2}{0.05-x}\left(0.05-x\right)$
$0.513\left(0.05-x\right)=4x^2$
We are then going to use the distributive property. Since we also know that the opposite of an number that is squared is the square root, we can also apply that. We would be left with something like this:
$x=-\frac{0.513+\sqrt{0.673569}}{8},\:x=\frac{\sqrt{0.673569}-0.513}{8}$
The variable $x$ can be both positive or negative.
We have found successfully our answer.

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish<span />