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3 years ago

15

I'm really not sure how to go about solving this algebraic equation, please help! .513 = (2x)^2 / (.05-x)

1 answer:

LiRa [457]3 years ago

4 0

Let's set it up like this:
$0.513=\frac{\left(2x\right)^2}{\left(0.05-x\right)}$
Multiply both sides by $0.05-x$
$0.513\left(0.05-x\right)=\frac{\left(2x\right)^2}{0.05-x}\left(0.05-x\right)$
$0.513\left(0.05-x\right)=4x^2$
We are then going to use the distributive property. Since we also know that the opposite of an number that is squared is the square root, we can also apply that. We would be left with something like this:
$x=-\frac{0.513+\sqrt{0.673569}}{8},\:x=\frac{\sqrt{0.673569}-0.513}{8}$
The variable $x$ can be both positive or negative.
We have found successfully our answer.

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish<span />

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4 years ago

Vertically stretched by a factor of 2, then translated<br> 4 units left and 1 unit down

drek231 [11]

A vertical stretch of scale factor 2, followed by a translation of 4 units left and 1 unit down is written as:

g(x) = 2*f(x + 4) - 1

<h3>How to write the given transformation?</h3>

For a general function f(x), a vertical stretch of scale factor K is written as:

g(x) = K*f(x).

<u><em>Horizontal translation:</em></u>

For a general function f(x), a horizontal translation of N units is written as:

g(x) = f(x + N).

If N is positive, the shift is to the left.
If N is negative, the shift is to the right.

<u><em>Vertical translation:</em></u>

For a general function f(x), a vertical translation of N units is written as:

g(x) = f(x) + N.

If N is positive, the shift is upwards.
If N is negative, the shift is downwards.

So, if we start with a function f(x) and we stretch it vertically with a scale factor of 2, we get:

g(x) = 2*f(x)

Then we translate it 4 units left:

g(x) = 2*f(x + 4)

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brainly.com/question/4289712

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2 years ago

Find the equation of a parabola with a vertical axis and its vertex at the origin and passing through the point (-2, 3).

jonny [76]

Answer:

$y=\frac{3}{4}x^2$

Step-by-step explanation:

Hi there!

Because we're given the vertex of the parabola, we can determine its equation in vertex form:

$y=a(x-h)^2+k$ where the vertex is $(h,k)$

Plug in the vertex (0,0)

$y=a(x-0)^2+0\\y=a(x)^2\\y=a(x-0)^2+0\\y=ax^2$

Now, we must solve for a. Plug in the given point (-2,3) and solve for a:

$3=a(-2)^2\\3=4a\\\frac{3}{4} =a$

Therefore, the value of a is $\frac{3}{4}$ . Plug this back into $y=ax^2$ :

$y=\frac{3}{4}x^2$

I hope this helps!

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3 years ago

Simplify by combining like terms -5a-4a+b

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3 years ago

5/4 (x - 5)= -6 what is x?

seropon [69]

So, you want to do the operations on both sides.
5/4 (x-5)=-6 becomes
x-5= -6/(5/4)
becomes
x= -6/(5/4)+5

and x=0.2
Hope this helped!

5 0

3 years ago

Read 2 more answers