It’s either A or B <br> I believe it might be A <br> Not sure

C is the center of the circle. Find the area of the segment shown in the figure,

Semmy [17]

Answer: A 28.50 sq. u

Step-by-step explanation:

In the given figure , radius of the circle : r= 10 u

Central angle made by Arc ED: $\theta$ = 90° ( right angle )

Now , the area of the segment is given by :-

Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)

Formula : Area of right triangle = 0.5 x Base x Height

Area of sector = $\dfrac{\theta}{360^{\circ}}\times\pi r^2$

Using above formulas in (i) and substituting corresponding values , we get

Area of segment =

$\dfrac{90^{\circ}}{360^{\circ}}\times\pi (10)^2-0.5\times10\times10\\\\=\frac{1}{4}(3.14)(100)-50\\\\=78.5-50=28.5\ sq.u$

Hence, the correct answer is A 28.50 sq. u

6 0

3 years ago

Write the standard form of 2 (4x - 1)(2x + 5)

kobusy [5.1K]

Answer:

16x^2+36x-10

Step-by-step explanation:

2 (4x - 1)(2x + 5)

=2(8x^2-2x+20x-5)

=2(8x^2+18x-5)

=16x^2+36x-10

7 0

3 years ago

How do I get the answer for 1 1/2 x 3 x 1 1/9

Mekhanik [1.2K]

$\boxed{1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}=5}$

<h2>Explanation:</h2>

in this problem we have the following expression:

$1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}$

So here:

$1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions$

Let's convert them as improper fractions:

$1 \frac{1}{2}=1+\frac{1}{2}=\frac{1\times 2+1}{2}=\frac{3}{2} \\ \\ 1 \frac{1}{9}=1+\frac{1}{9}=\frac{1\times9 +1}{9}=\frac{10}{9}$

Rewriting our expression:

$\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5$

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

#LearnWithBrainly

3 0

3 years ago

Which of the following is a prime number 6765 63 + 60

natulia [17]

Your answer is 67 hope this helps

6 0

3 years ago

Consider the vectors x=(1,2,3,4) and y=(4,2,4,5) in R4 . Find the angle between them.

Law Incorporation [45]

Answer:

Angle between the two vectors is 20.7718°.

Step-by-step explanation:

The given two vectors are x = (1,2,3,4) and y = (4,2,4,5)

Now the dot product between two vector is defined as

x.y = ║x║║y║cosθ

Now, x.y( dot product of x and y) = 1×4 + 2×2 + 3×4 + 4×5 = 40

║x║= $\sqrt{1+4+9+16}$ = $\sqrt{30}$

║y║= $\SQRT{16+4+16+25} = \sqrt{61}$ '

Thus, we get

40 = $\sqrt{30}$ × $\sqrt{61}$ ×Cos θ

Thus, Cos θ = $\frac{40}{\sqrt{30}\sqrt{61}}$

Cos θ = 0.935

θ = $Cos^{-1} (0.935)$

θ = 20.7718°

4 0

3 years ago

It’s either A or B I believe it might be A Not sure