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Lady_Fox [76]
3 years ago
13

Kylie sells 2 concert tickets every minute. She has already sold 8 tickets. If f(t) represents the total number of tickets that

Kylie will sell in t minutes, which of the following functions represents the relationship between f(t) and t? f(t) = 8t − 2 f(t) = 2t − 8 f(t) = 2t + 8 f(t) = 8t + 2
Mathematics
1 answer:
Vilka [71]3 years ago
4 0
2tickets per min=2t
minus the 8 tickets she already had -8

f(t)=2t-8
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The product of 4x and 0 is:<br> A. 4x<br> B. 4<br> C. 0<br> D. None of these
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C. 0

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A calculator screen shows a number in scientific notation as 1.04E10. Write this number in standard form.
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3 0
3 years ago
The number of chocolate chips in a popular brand of cookie is normally distributed with a mean of 22 chocolate chips per cookie
MA_775_DIABLO [31]

Answer:

The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 22, \sigma = 3.5

Middle 90%

Between the 50 - (90/2) = 5th percentile to the 50 + (90/2) = 95th percentile.

5th percentile:

X when Z has a pvalue of 0.05. So X when Z = -1.645.

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 22}{3.5}

X - 22 = -1.645*3.5

X = 16.242

95th percentile:

X when Z has a pvalue of 0.95. So X when Z = 1.645.

Z = \frac{X - \mu}{\sigma}

1.645 = \frac{X - 22}{3.5}

X - 22 = 1.645*3.5

X = 27.758

The cutoff numbers for the number of chocolate chips in acceptable cookies are 16.242 and 27.758

3 0
3 years ago
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