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2 years ago

Choose 5 ordered pairs whose second component is the opposite of the first component.

1 answer:

8 0

The 5 ordered pairs whose second component is the opposite of the first component are (-1,1), (-2,2), (-3,3), (-4,4) and (-5, 5).

Ordered pairs:

An ordered pairs is a composition of the x coordinate and the y coordinate (ordinate), having two values written in a fixed order within parentheses.

It can be written as (a,b).

Here

a represents the x coordinate and

b represents the y coordinate.

It helps to locate a point on the Cartesian plane for better visual comprehension.

Given:

The second component is the opposite of the first component.

Here we need to find the 5 ordered pairs for that.

For the given statement,

Let x be the first component and y be the second component.

So it can be written as,

=> y = -x

So, the five ordered pairs are,

=> 1 = -1

=>2 = -2

=> 3 = -3

=> 4 = -4

=> 5 = -5

So, the ordered pairs are,

(x,y) => (-1,1), (-2,2), (-3,3), (-4,4) and (-5, 5).

To know more about Ordered Pairs here.

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Find the length indicated. find CE

torisob [31]

Okay, to find length CE, your going to know the value of x. Length BC + CE = BD + DE.
3x+47+x+26=27+x+10
Simplify the equation to get
4x+73=37+x
you can choose one of four ways to continue, but I will choose to subtract x
3x+73=37
Subtract 73 from both sides of the equal sign
3x=-36
divide by 3 on both sides of the equal sign to get the value of x
x=-12

Now, plug in -12 for x in length CE to get -12+26=14

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4 years ago

Click the location of the point in the coordinate plane with the coordinates (–4, 3).

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Answer:

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Step-by-step explanation:

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3 years ago

Evaluate 50 + 0.5 ×(41 - 32)

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3 years ago

How to determine if Triangles are Congruent?

IRISSAK [1]

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3 years ago

A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye

Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we select appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{x}=n\mu$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{x}=\sqrt{n}\sigma$

The information provided is:

μ = $970

σ = $129

n = 102

Since the sample size is quite large, i.e. n = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

$\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)$

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

$P (\sum X \leq 100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}$

$=P(Z$

*Use a z-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

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3 years ago