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zlopas [31]
2 years ago
15

Choose 5 ordered pairs whose second component is the opposite of the first component.

Mathematics
1 answer:
melamori03 [73]2 years ago
8 0

The 5 ordered pairs whose second component is the opposite of the first component are (-1,1), (-2,2), (-3,3), (-4,4) and (-5, 5).

Ordered pairs:

An ordered pairs is a composition of the x coordinate and the y coordinate (ordinate), having two values written in a fixed order within parentheses.

It can be written as (a,b).

Here

a represents the x coordinate and

b represents the y coordinate.

It helps to locate a point on the Cartesian plane for better visual comprehension.

Given:

The second component is the opposite of the first component.

Here we need to find the 5 ordered pairs for that.

For the given statement,

Let x be the first component and y be the second component.

So it can be written as,

=> y = -x

So, the five ordered pairs are,

=> 1 = -1

=>2 = -2

=> 3 = -3

=> 4 = -4

=> 5 = -5

So, the ordered pairs are,

(x,y) => (-1,1), (-2,2), (-3,3), (-4,4) and (-5, 5).

To know more about Ordered Pairs here.

brainly.com/question/23922144

#SPJ4

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Answer:

probability of bag one 62.5% for blue marbles green- 37.5%

probability of bag 2 66.67% for yellow and for blue 33.33%

he will probably get a blue and yellow marble

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7 0
3 years ago
Melissa and Brian are at the base of a mountain. Melissa hikes to
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67 meters because if you use the triangle congruent method with the altitude at 65 degrees you should get the right answer
8 0
3 years ago
There are 27 students in Ms. Langley's
Yuliya22 [10]

Answer:

405 Problems

Step-by-step explanation:

  • One student in class has 15 problems.
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<em>In all, there would be 405 problems assigned to the whole class.</em>

8 0
3 years ago
If Kevin wants a 90 average in math after 5 tests and his first 4 tests are 76, 92, 89 and 97 what does he need on the fifth tes
Keith_Richards [23]
You need to understand that you're solving for the average, which you already know: 90. Since you know the values of the first three exams, and you know what your final value needs to be, just set up the problem like you would any time you're averaging something.
Solving for the average is simple:
Add up all of the exam scores and divide that number by the number of exams you took.
(87 + 88 + 92) / 3 = your average if you didn't count that fourth exam.
Since you know you have that fourth exam, just substitute it into the total value as an unknown, X:
(87 + 88 + 92 + X) / 4 = 90
Now you need to solve for X, the unknown:
87
+
88
+
92
+
X
4
(4) = 90 (4)
Multiplying for four on each side cancels out the fraction.
So now you have:
87 + 88 + 92 + X = 360
This can be simplified as:
267 + X = 360
Negating the 267 on each side will isolate the X value, and give you your final answer:
X = 93
Now that you have an answer, ask yourself, "does it make sense?"
I say that it does, because there were two tests that were below average, and one that was just slightly above average. So, it makes sense that you'd want to have a higher-ish test score on the fourth exam.
4 0
4 years ago
Read 2 more answers
If you could help I would really appreciate it, but if not that’s fine. Thank you.
Svetradugi [14.3K]
Since 4 is between 2 & 5 you input it into the middle equation.

x=4

so the answer is 4!
7 0
3 years ago
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