<h2>The rock hits the ground between 2 and 2.5 seconds.</h2>
Step-by-step explanation:
The given table is:
t h(t)
0 20
0.5 18.8
1 15.1
1.5 9
2 0.4
2.5 -10.6
3 -24.1
The ground level is when h(t) = 0, which is between 0.4 and -10.6, because in that interval is included the zero. So, the problem is asking when does the rock hit the ground, referring to time. We just have to look for t-values for 0.4 and -10.6.
<em>Therefore, the rock hits the ground between 2 and 2.5 seconds.</em>
At 2 seconds, the height of the rock is 0.4 meters, and at 2.5 seconds the height of the rock is -10.6 meters. Therefore, the rock hit the ground, or 0 meters, between those times.
The answer is algebraic work. Algebra is a based math is the piece of arithmetic in which letters and other general images are utilized to speak to numbers and amounts in formulae and conditions.
I hope the answer will help you. Feel free to ask more questions.
