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MariettaO [177]
2 years ago
7

iif $a$, $b$, $c$, and $d$ are replaced by four distinct digits from $1$ to $9$, inclusive, then what's the largest possible val

ue of the difference $a.b - c.d$ ?
Mathematics
1 answer:
Zarrin [17]2 years ago
5 0

If a, b ,c ,d are replaced by four distinct digits from 1 to 9 , inclusive, then the largest possible value of the difference of the decimals (a.b) and (c.d)[(a.b - c.d)] will be 8.6.

As per question statement, a, b ,c ,d are replaced by four distinct digits from 1 to 9 , inclusive.

We are required to calculate the largest possible value of the difference of the decimals (a.b) and (c.d).

Now, clearly, to obtain the largest difference between two decimals (a.b) and (c.d), (a.b) has to be the largest possible decimal within the given conditions and (c.d) has to be the least possible decimal.

Now, the largest decimal we can from using the numbers (1 to 9) is 9.8 and the smallest decimal we can from using the numbers (1 to 9) is 1.2.

That is, [(a.b) = (9.8)] and [(c.d) = (1.2)]

And, the difference of the Largest Decimal and the least decimal is bound to be the largest.

Therefore, (a.b - c.d)= (9.8 - 1.2) = 8.6.

  • Decimal: relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten, a decimal is a fraction whose denominator is a power of ten and whose numerator is expressed by figures placed to the right of a decimal point.

To learn more about decimals, click on the link below.

brainly.com/question/11852700

#SPJ4

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X+y=26<br> 3x+8y=123<br> What is x equal
Pani-rosa [81]

Answer:

x=17, y=9. (17, 9).

Step-by-step explanation:

x+y=26

3x+8y=123

------------------

x=26-y

3(26-y)+8y=123

78-3y+8y=123

78+5y=123

5y=123-78

5y=45

y=45/5

y=9

x=26-9=17

5 0
4 years ago
PLEASE HELP!!!! 20 POINTS!!!
Vlad1618 [11]
Mass = density* volume
since density= mass/volume then mass/volume*volume=mass
= 4.5*0.4 =  1.80g

6 0
3 years ago
In the following table of values, the first differences are
ExtremeBDS [4]

Answer:

-7

Step-by-step explanation:

Given

\begin{array}{ccc}x & {y} & {First\ difference} & {-2} & {34} & {}&{-1} & {27} & {} &{0} & {20} & {} & {1} & {13} & {} & {2} & {6} &{} \ \end{array}

Required

The first difference

To do this, we simply calculate the difference between the consecutive y-values.

i.e.

d = y_{n+1} - y_n

So, we have:

d = y_2 - y_1 = 27 - 34 = -7

d = y_3 - y_2 = 20 - 27 = -7

d = y_4 - y_3 = 13 - 20 = -7

d = y_5 - y_4 = 6-13 = -7

<em>Hence, the first differences are -7 (all through)</em>

5 0
3 years ago
SOLVE THIS EXTREMELY IMPORTANT EQUATION
finlep [7]

Answer:

<em>Option B; EF = ( About ) 4.47 units, Perimeter of Δ EFG = ( About ) 12.94 units</em>

Step-by-step explanation:

If we were to consider the height of this triangle EFG, it would be 4 units of length, supposedly splitting base GF into two ≅ parts, each 2 units of length. First let us name the point drawn to base GF ⇒ point H, so that the height of Δ EFG ⇒ EH. Now as EH splits GF into two ≅ parts, by Converse to Coincidence Theorem, Δ EFG ⇒ Isosceles Δ;

EH and FH are legs of a right triangle EFH, so that Pythagorean Theorem can be applied to solve for the length of EF and EG, knowing that as Δ EFG ⇒ Isosceles Δ, EF ≅ EG;

( EH )^2 + ( FH )^2 = ( EF )^2,

( 4 )^2 + ( 2 )^2 = ( EF )^2 ⇒ take square of 4 & 2,

16 + 4 = ( EF )^2 ⇒ combine like terms,

( EF )^2 = 20 ⇒ take square root on either side to solve for EF,

EF = √ 20 =<em> ( About ) 4.47 units</em> = EG,

Perimeter of Δ EFG = EF + GF + EG = 4.47 + 4 + 4.47 = <em>( About ) 12.94 units,</em>

<em>Solution; Option B</em>

6 0
3 years ago
The sum of two integers is 26. the sum of the squares of the two integers is 340. what is the product of the two numbers?
Phoenix [80]
Lets say that the two unknown integers are n and m.

We know the following things about n and m:

n+m=26
n^2+m^2=340

And, we want to find nm.

To solve this, we'll use the expansion of the squared of the sum of any two inegers; this is expressed as:

(n+m)^2=n^2+2nm+m^2

So, given what we know about the unknown integers, the previous can be written as:

(26)^2=340+2nm

We can easily solve for nm:

nm= \frac{(26)^2-340}{2}= \frac{676-340}{2}= \frac{336}{2}=168

The answer is 168.

Another approach to solve the problem is, from the two starting equations, compute the values of n and m, which are 12 and 14, and directly compute their product; however, the approach described is more elegant. 
5 0
3 years ago
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