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tatiyna
1 year ago
11

Evaluate (x^2 + x-2) ➗ (2x^2 + X-3) when X= -1

Mathematics
1 answer:
konstantin123 [22]1 year ago
3 0

Answer:

6

Step-by-step explanation:

(-1^2 + -1-2) / (2*-1^2 + -2-3)

1 + -3 / 2 + -5

-2 / -3

= 6

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Step-by-step explanation:

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3 years ago
What is the solution to -4|-2x+6| = -24
AURORKA [14]
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3 years ago
Which two quadrants have negative x-values?
mart [117]

Answer:

II and III  ( 2 and 3)

Step-by-step explanation:

The quadrants are numbered counter clockwise, with the top right being number I

II                I

III                IV

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3 0
2 years ago
Help asap please ----------------
melomori [17]

Answer:

-1 Not in domain

0 In domain

1 In domain

Step-by-step explanation:

The domain for the square root function is all positive numbers including (0). The domain is the set of real numbers which when substituted into the function will produce a real result. While one can substitute a negative number into the square root function and get a result, however, the result will be imaginary. Therefore, the domain for the square root function is all positive numbers. It can simply be expressed with the following inequality:

x\geq0

Therefore, one can state the following about the given numbers. Evaluate if the number is greater than or equal to zero, if it is, then it is a part of the domain;

-1 => less than zero; Not in domain

0 => equal to zero; <em> </em>In domain

1  => greater than zero: In domain

4 0
3 years ago
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Alchen [17]
I think it’s C not sure tho
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