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mario62 [17]
3 years ago
11

What is 19 1/2% of 62?

Mathematics
2 answers:
Tanya [424]3 years ago
6 0

Answer:

12.09

Step-by-step explanation:

Easy way to find percent of a number is multiplying it by a decimal. For your problem, 62 × .195 Though with the 1/2, just to make sure I did it like this: 62 × 0.19 = 11.78 (for the 19%) then 62 × 0.005 = 0.31 This all equaled to 12.09! :)

Alborosie3 years ago
4 0

Answer:

12.09

done on calculator.

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Answer:

The correct options are;

A. 120

B. 34

Step-by-step explanation:

The given parameters are;

Required to find how many of the permutations of 1, 2, 3, 4, 5, 6, have 1, 2, 3 arranged one after the other in the given order

Requirement to arrange 6 digits, 1, 2, 3, 4, 5, 6 in the order such that 1, 2, and 3 always appear in turn, they are as follows

When the first digit is 1, and the 2nd digit is 2 the number of ways of selecting the other  digits is 24

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1, 2, 3, 4, 5, 6,                                               24

1, 4, 2,                                                            18

1, 4, 5, 2,                                                        12

1, 4, 5, 6, 2,                                                     6

4, 1, 2,                                                             18

4, 1, 5, 2,                                                         12

4, 1, 5, 6,                                                         6

4, 5, 1, 2,                                                         12

4, 5, 1, 4, 2                                                      6

4, 6, 5,                                                            6

Total = 24 + 18 + 12 + 6 + 18 + 12 + 6 + 12 + 6 + 6 = 120 ways

The correct option is A. 120

2. The dimensions of the original rectangle = L by W

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The possible integers that have a product of 10 are;

1 × 10 and 5 × 2

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Which gives the perimeters as 2*(15 + 2) = 34 or 2*(7.5 + 4) = 23

Therefore, the largest possible rectangle is 34

The correct option is B. 34.

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