Please help me !! Show work if possible
1 answer:
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Answer:
see below
Step-by-step explanation:
The slopes of parallel lines are the same. The slopes of perpendicular lines are negative reciprocals of each other, hence their product is -1.
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For the most part, the concept of adding slopes of lines does not relate to parallel or perpendicular lines in any way.
Try this:
Given:
![\left \{ {{x-y=1} \ [1] \atop {x+y=3} \ [2]} \right.](https://tex.z-dn.net/?f=%20%5Cleft%20%5C%7B%20%7B%7Bx-y%3D1%7D%20%5C%20%5B1%5D%20%5Catop%20%7Bx%2By%3D3%7D%20%5C%20%5B2%5D%7D%20%5Cright.%20)
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)
Given:
1) [1]+[2]: 2x=2 ⇒ x=2
2) [2]-[1]: 2y=1 ⇒ y=1.
3) answer: (2;1)