To determine the number of possible arrangements for 6 out of 8, we should use combinations. That is
ₐC₆ = 8!/(6!2!)
Answer: b. Combination
We are given these three people age below:
- Jim's age
- Carla's age
- Tomy's age
We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.
Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.
Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).
The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

Combine like terms and solve for x.

Then we substitute the value of x in ages to find these three people ages.
- Jim's age = x = 5
- Carla's age = x+5 = 5+5 = 10
- Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.
Answer
- Jim's age = 5
- Carla's age = 10
- Tomy's age = 16
Answer:
pretty sure its 645ml
Step-by-step explanation:
Answer:
x2 - 10x - 1994
Step-by-step explanation:
Step 1 :
Trying to factor by splitting the middle term
1.1 Factoring x2-10x-1994
The first term is, x2 its coefficient is 1 .
The middle term is, -10x its coefficient is -10 .
The last term, "the constant", is -1994
Step-1 : Multiply the coefficient of the first term by the constant 1 • -1994 = -1994
Step-2 : Find two factors of -1994 whose sum equals the coefficient of the middle term, which is -10 .
-1994 + 1 = -1993
-997 + 2 = -995
-2 + 997 = 995
-1 + 1994 = 1993
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
Final result :
x2 - 10x - 1994
Processing ends successfully
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The answer is 90..........................................................................................