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IgorC [24]
1 year ago
10

Injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and ri

ght sides. THe area of the square feet. What is the length of the track? Use the table to help you answer the questions.
Mathematics
1 answer:
Savatey [412]1 year ago
8 0

The track is a square with half circle on its right and left side. The area of the square is 128 feet². The length is 22.6 feet

<h3>How to illustrate the information?</h3>

It should be noted that the area of the square will be:

= x².

Therefore, 128 = x².

x ,= ✓128

x = 11.3

Therefore the radius of the circle will be:

= 11.3/2

= 5.65

The length of the truck will be:

= 11.3 + 5.65 + 5.65

= 22.6

The length is 22.6 feet

Learn more about square in:

brainly.com/question/17658108

#SPJ1

Injured runners train on a special track at a rehabilitation center. The track is a square with a half circle on its left and right sides. The area of the square is 128 square feet. What is the length of the track? Use the table to help you answer the questions.

Square 11.02 11.12 11.22 11.32 11.42 11.52

Value 121.0 123.2 125.4 127.7 130.0 132.3

Square 11.62 11.72 11.82 11.92 12.02

Value 134.6 136.9 139.2 141.6 144.0

1. Fill in the blanks to complete the description of the track.

The track has ____ sides of the square and the distance around

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Analyze the diagram below and complete the instructions that follow. Find a, b, and c.
ahrayia [7]

Answer:

<u>The correct answer is the letter C. </u>

Step-by-step explanation:

We can use the following trigonometric identity:

cos(60)=\frac{6}{b} (1)

cos(45)=\frac{c}{b} (2)

Solving each equation by b and equaling we have:

\frac{6}{cos(60)}=\frac{c}{cos(45)}

\frac{6}{cos(60)}=\frac{c}{cos(45)}

Let's recall that:

cos(45)=\frac{1}{\sqrt{2}}

cos(60)=\frac{1}{2}

Then we have:

c=\frac{cos(45)*6}{cos(60)}

c=\frac{2*6}{\sqrt{2}}

c=\frac{12}{\sqrt{2}}

c=6\sqrt{2}

Using equation (1) we can find b.

cos(60)=\frac{6}{b}  

b=12      

Finally, we can find a using the next equation:

tan(60)=\frac{a}{6}

a=6*tan(60)

a=6\sqrt{3}

<u>Therefore, the correct answer is the letter C. </u>

I hope it helps you!

5 0
2 years ago
Solve this inequality: 3b – 7 &lt; 32
butalik [34]
It's a lot like solving equations.

3b-7 < 32
Add 7 to each side.
3b < 39
Divide by 3 on each side.
b < 13

Hope this helps :)
6 0
3 years ago
Read 2 more answers
dude, I just got almost all of my points taken away from somebody that has 0 answers, 0 questions, and almost 2 million points..
Finger [1]

Answer:

:O

Step-by-step explanation:

7 0
3 years ago
Find the magnitude of the vector &lt;−4, −6&gt;.<br><br> 8<br> 7.2<br> 10<br> 6.4
PolarNik [594]

The magnitude of the vectors is 7.2

The magnitude of a vector is resolved by using a formula

<h3>Magnitude of a Vector</h3>

This is the displacement between two vectors and can be calculated as

x^2 = y^2 + z^2\\x = \sqrt{y^2 + z^2} \\

where x is the magnitude of displacement between y and z.

In this question, the vectors are

  • -4
  • -6

Let's find the magnitude of this vector

x = \sqrt{(-4)^2+(-6)^2}\\x = \sqrt{16+36}\\x = \sqrt{52}\\x = 7.2

The magnitude of the vectors is 7.2

Learn more on magnitude of vectors here;

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4 0
2 years ago
I have no idea how to do this, please help!
Marta_Voda [28]

Answer:

24

Step-by-step explanation:

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