This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
Answer:
x=2, y=-1, z=3
Step-by-step explanation:
The system shown in the attached picture can be solved using any method you wish
I think that the best way to go is by using the subtraction method,
First multiply the equation x+y+z=4 by 2, then sum it to the second equation.
This gives another equation: 4x+z=11.
If we subtract the first eq. with the third, we have another eq. -5x+z=-7.
Lest sum the 2 new founded equations, to obtain the following result: -9x=-18
thus, we obtain x=2
Next lets go backwards in the prior eq -5x+z=-7, with x=2, we obtain that z=3
Now in the first equation (x+y+z=4) we can substitute x=2, z=3 to obtain y value.
Answer:A
Step-by-step explanation:
Answer: They must sell 116 more boxes to raise $270.
Solution:
For every box they sell, they get $1.35 profit.
They have sold 84 boxes already, then they have:
$1.35 * 84 = $113.40
They need $270, then they have to sell:
$270-$113.40=$156.60
For every box they sell, they get $1.35 profit, then they need to sell:
$156.60/$1.35=116 more boxes
Check:
116*$1.35=$156.60
84*$1.35=$113.40
$156.60+$113.40=$270.00
F(x) = 3x² + 5x - 8 g(x) = 2x² - 9
5.
f(2) = 3(2²) + 5(2) - 8 g(2) = 2(2²) - 9
f(2) = 3(4) + 10 - 8 g(2) = 2(4) - 9
f(2) = 12 + 10 - 8 g(2) = 8 - 9
f(2) = 14 g(2) = -1
i didn't understand the second part but i hope you understand, God bless!