Answer
Find out the number of hours when the cost of parking at both garages will be the same.
To prove
As given
There are two parking garages in beacon falls .
As given
Let us assume that the y is representing the cost of parking at both garages will be the same.
The total number of hours is represented by the x.
First case
Garage a charges $7.00 to park for the first 2 hours ,and each additional hour costs $3.00 .
As garage charges $7.00 for the first 2 hours so the remaning hours are (x -2)
Than the equation becomes
y = 3.00 (x -2) + 7.00
written in the simple form
y = 3x - 6 +7
y = 3x + 1
Second case
Garage b charges $3.25 per hour to park.
than the equation becomes
y = 3.25x
Compare both the equations
3x +1 = 3.25x
3.25x -3x = 1
.25x = 1

x = 4hours
Therefore in the 4 hours the cost of parking at both garages will be the same.
Answer:
Step-by-step explanation
6n - 6 = 2 (n+1)
Simplify 2 (n+1)
6n - 6= 2n +2
Move all terms related to n to the left side of the equation
4n -6 =2
Move all terms not related to n to the right side of the equation
4n =8
Divide each term by 4 then simplify
n=2
Answer:
total amount paid = $ 22.9
Step-by-step explanation:
total price = $ 2.5 + $3.4(6)= $22.9
Answer:
10 cm
Step-by-step explanation:
a^2 + b^2 =c^2
6^2 + 8^2 = c^2
36 + 64 = 100
then find the square root of 100 which equals 10
Answer:
Step-by-step explanation:
3/8 miles long, 1/48 miles per hour
3/8 and 1/48 can have a common denominator, so you make 3/8 into 18/48 by multiplying both the numerator and denmoinator by 6.
18/48 miles long
1/48 per hour
divide: 18/48 divided by 1/48, which turns into 18/48 x 48/1 which equals 18
18 hours