What is the sqaure root of 6475839

Vika [28.1K]

When solving the equation, you first have h- 9/5. So it would by x=(h - 9/5). But you are not done yet. you still have to divide it by R to get x. So the final equation is x=(h - 9/5) ÷ R

7 0

3 years ago

The length of a rectangle is 3 centimeters less than four times its width. Its area is 10 square centimeters. Find the dimension

Kay [80]

Answer:

W = 2 cm

L = 5 cm

Step-by-step explanation:

A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. Its area, the amount of space inside it, can be found using the formula A = l*w. If the area is 10 cm² and the length is "3 cm less than 4 times the width" or 4w - 3, you can substitute and solve for w.

A = l*w

10 = (4w - 3)(w)

10 = 4w² - 3w

Subtract 10 from both sides to make the equation equal to 0. Then solve the quadratic by quadratic formula.

4w² - 3w - 10 = 0

Substitute a = 4, b = -3 and c = -10.

$w = \frac{3 +/- \sqrt{(-3)^2 - 4(4)(-10)} }{2(4)} = \frac{3 +/- \sqrt{9 +160)} }{8} = \frac{3 +/- \sqrt{169} }{8} = \frac{3+/-13}{8}$

There are two possible solutions which can be found.

3 + 13 / 8 = 16/ 8 = 2

3 - 13 / 8 = -10/8 = -5/4

Since w is a side length or distance, it must be positive so w = 2 cm.

If the width is 2 cm then the length is 4(2) - 3 = 8 - 3 = 5 cm.

8 0

2 years ago

Can you explain it and help me out please

Anarel [89]

Answer:

c.

Step-by-step explanation:

2x² - 4x - 3 = 0

$x= \frac{-b+/-\sqrt{b^{2}-4ac} }{2a} \\\\x= \frac{-(-4)+/-\sqrt{(-4)^{2}-4*2*(-3)} }{2*2} \\\\x= \frac{4+/-\sqrt{16+24} }{4} \\\\x= \frac{4+/-\sqrt{40} }{4} = \frac{4+/-2\sqrt{10} }{4}=\frac{2+/-\sqrt{10} }{2}$