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Kisachek [45]
2 years ago
8

Solve for m d=n+7m Thank you

Mathematics
2 answers:
Sphinxa [80]2 years ago
5 0

Answer:  \displaystyle m = \frac{d-n}{7}

This is the same as writing m = (d-n)/7

The parenthesis are essential for the second format because it tells us to divide all of (d-n) over 7, and not just n over 7.

============================================================

Explanation:

Here is one way to solve for m. I'll go over each step in the next section below.

d = n+7m\\\\n+7m = d\\\\7m = d-n\\\\m = \frac{d-n}{7}

The idea is to get the variable m by itself.

Think of n+7m as 7m+n since we can add in any order. Then undo the "plus n" portion by subtracting n from both sides (step 3).

In the 4th step, I divided both sides by 7 to undo the multiplication that is going on with 7m aka 7*m

In general we follow PEMDAS backwards to undo each operation done to the variable we're solving for. Let me know if you have any questions about what I mean.

Brut [27]2 years ago
3 0

Answer:

m=d/7−n/7

Step-by-step explanation:

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Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
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Answer:

The correct answer is:

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C. Trisha is shorter than 75% of girls aged 16 to 18.

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3 years ago
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Sergeeva-Olga [200]
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In a standard deck of cards, what is the probability of drawing a red card or a face card? answer choices are in the form of a p
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Answer:

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Step-by-step explanation:

No math required since it is Infinite Solutions. :-)

6 0
2 years ago
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