All categories

2 years ago

Solve for m d=n+7m Thank you

Mathematics

2 answers:

Sphinxa [80]2 years ago

5 0

Answer: $\displaystyle m = \frac{d-n}{7}$

This is the same as writing m = (d-n)/7

The parenthesis are essential for the second format because it tells us to divide all of (d-n) over 7, and not just n over 7.

============================================================

Explanation:

Here is one way to solve for m. I'll go over each step in the next section below.

$d = n+7m\\\\n+7m = d\\\\7m = d-n\\\\m = \frac{d-n}{7}$

The idea is to get the variable m by itself.

Think of n+7m as 7m+n since we can add in any order. Then undo the "plus n" portion by subtracting n from both sides (step 3).

In the 4th step, I divided both sides by 7 to undo the multiplication that is going on with 7m aka 7*m

In general we follow PEMDAS backwards to undo each operation done to the variable we're solving for. Let me know if you have any questions about what I mean.

Brut [27]2 years ago

3 0

Answer:

m=d/7−n/7

Step-by-step explanation:

You might be interested in

n a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of inches and a stand

kotykmax [81]

Answer:

(a) The probability that a study participant has a height that is less than 67 inches is 0.4013.

(b) The probability that a study participant has a height that is between 67 and 71 inches is 0.5586.

(c) The probability that a study participant has a height that is more than 71 inches is 0.0401.

(d) The event in part (c) is an unusual event.

Step-by-step explanation:

The complete question is: In a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of 67.5 inches and a standard deviation of 2.0 inches. A study participant is randomly selected. Complete parts (a) through (d) below. (a) Find the probability that a study participant has a height that is less than 67 inches. The probability that the study participant selected at random is less than inches tall is nothing. (Round to four decimal places as needed.) (b) Find the probability that a study participant has a height that is between 67 and 71 inches. The probability that the study participant selected at random is between and inches tall is nothing. (Round to four decimal places as needed.) (c) Find the probability that a study participant has a height that is more than 71 inches. The probability that the study participant selected at random is more than inches tall is nothing. (Round to four decimal places as needed.) (d) Identify any unusual events. Explain your reasoning. Choose the correct answer below.

We are given that the heights in the 20-29 age group were normally distributed, with a mean of 67.5 inches and a standard deviation of 2.0 inches.

Let X = the heights of men in the 20-29 age group

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean height = 67.5 inches

$\sigma$ = standard deviation = 2 inches

So, X ~ Normal( $\mu=67.5, \sigma^{2}=2^{2}$ )

(a) The probability that a study participant has a height that is less than 67 inches is given by = P(X < 67 inches)

P(X < 67 inches) = P( $\frac{X-\mu}{\sigma}$ < $\frac{67-67.5}{2}$ ) = P(Z < -0.25) = 1 - P(Z $\leq$ 0.25)

= 1 - 0.5987 = 0.4013

The above probability is calculated by looking at the value of x = 0.25 in the z table which has an area of 0.5987.

(b) The probability that a study participant has a height that is between 67 and 71 inches is given by = P(67 inches < X < 71 inches)

P(67 inches < X < 71 inches) = P(X < 71 inches) - P(X $\leq$ 67 inches)

P(X < 71 inches) = P( $\frac{X-\mu}{\sigma}$ < $\frac{71-67.5}{2}$ ) = P(Z < 1.75) = 0.9599

P(X $\leq$ 67 inches) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{67-67.5}{2}$ ) = P(Z $\leq$ -0.25) = 1 - P(Z < 0.25)

= 1 - 0.5987 = 0.4013

The above probability is calculated by looking at the value of x = 1.75 and x = 0.25 in the z table which has an area of 0.9599 and 0.5987 respectively.

Therefore, P(67 inches < X < 71 inches) = 0.9599 - 0.4013 = 0.5586.

(c) The probability that a study participant has a height that is more than 71 inches is given by = P(X > 71 inches)

P(X > 71 inches) = P( $\frac{X-\mu}{\sigma}$ > $\frac{71-67.5}{2}$ ) = P(Z > 1.75) = 1 - P(Z $\leq$ 1.75)

= 1 - 0.9599 = 0.0401

The above probability is calculated by looking at the value of x = 1.75 in the z table which has an area of 0.9599.

(d) The event in part (c) is an unusual event because the probability that a study participant has a height that is more than 71 inches is less than 0.05.

7 0

3 years ago

Which is a correct expansion of (2x+3)(2x^{2} -5)?

Travka [436]

Answer:

4x^{3} + 6x^{2} -10x -15

Step-by-step explanation:

(2x+3)(2x^{2} -5)

2x × 2x^{2} + 2x× (-5) + 3× 2x^{2} + 3 ×(-5)

=4x^{3} -10x + 6x^{2} -15

= 4x^{3} + 6x^{2} -10x -15

7 0

4 years ago

Image of question. Thank you very much!

Valentin [98]

the answer is -111,111.1111111111

6 0

4 years ago

Please solve this and please explain! Thankyou!

tester [92]

Answer:

Step-by-step explanation:

When n = 6, the length is 3 * 6 + 2 = 20 and the width is 6 - 1 = 5. We know that the perimeter of the rectangle is twice the sum of its length and width. The sum of the length and width is 20 + 5 = 25 and twice that is 25 * 2 = 50.

5 0

3 years ago

Read 2 more answers

Ben is 5 years less than 3 times Gracie's age. How can that be represented as an expression?

Maksim231197 [3]

Answer:

b=3g-5

Step-by-step explanation:

3 times Gracie's age = 3g

Ben is 5 years less = -5

3g-5=Ben

Ben=3g-5

Hope this helped! :^)

3 0

4 years ago

Read 2 more answers