Answer:
answer : B
Step-by-step explanation:
( x + 7) (3x -2) = 3x² - 2x +21x -14
( x + 7) (3x -2) = 3x²+19x -14
U should use friendly numbers when subtracting.......the numbers have to be between 3 and 10
Answer:
f(x) = (1/2)(x-2)^2(x+1)(x+2)
Step-by-step explanation:
You can determine this by looking at the zeroes of the graph. For any zero that goes through the x-axis, the power of that zero is odd. For any zero that that "bounces" from the x-axis, the power of that zero is even.
Starting from left to right, we can see that the first zero, -2, goes through the x-axis. That means (x+2) is raised to an odd power. The second zero, -1, also goes through, so (x+1) is raised to an odd power. The last zero, 2, bounces off the x-axis, so (x-2) is raised to an even power. The only functions that satisfy this criteria are function 1 and 2.
However, we are not done yet. We need to figure out which multiplier value (1/2, 1/4) is correct. To do this, we plug in 0 for x, since we know that the y-intercept is 4. When we plug in 0, we see that f(0) = 4 for the first function. Therefore, the first function is the answer.
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The process here is finding out the smallest number's % towards the largest number.
Divide 20 by 52:
20/52 = 0.38 (estimated) | This is the % in decimal form, which is 38%.
Conclusion: 20 is 38% of 52.
{---Further Elaboration for Future Reference---}
Finding the Smallest Number:
What number is 25% of 60?
Multiply 60 by the decimal form of 25%.
60 * 0.25 = 15 | 15 is 25% of 60.
Finding the Percentage. (Like what we already did.)
30 is what percent of 150?
Divide 30 by 150.
30/150 = 0.2 | 30 is 20% of 150.
Finding the Largest Number.
12 is 30% of what number?
Divide 12 by the decimal form of 30%.
12/0.3 = 40 | 12 is 30% of 40.
I hope this helps, have a great rest of your day! ^ ^
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Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
