Line is Passing through the Points (-3 , -1) and (-5 , 4)
Slope of a Line Passing through two points (x₁ , y₁) and (x₂ , y₂) is given by :
here x₁ = -3 and x₂ = -5 and y₁ = -1 and y₂ = 4
Irina has 10 coins, all nickels and dimes, worth a total of $0.70. This is shown by the system of linear equations, x + y = 10 a
1 answer:
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Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1