Use the distributive property to write an equivalent expression. 2(8v+2)

ILL MARK YOU THE BRAINLYEST PLEASE HELPPP look at attachment

tester [92]

Answer:

D; is the right answer hope it helps ;)

Step-by-step explanation:

3 0

2 years ago

Joseph put a 30% down payment on a house. What fraction of a down payment did Joseph put on a house?

marshall27 [118]

3/10 is the fraction that matches 30%.

7 0

2 years ago

PLEASE HELP!

3241004551 [841]

The question is incomplete. Here is the complete question.

The salary of members of two governing bodies in 2008 was $167.2 thousand, and has increased by approximately $2 thousand per year since then. Complete parts (a) and (b).

(a) Complete the following table to help find an expression that stands for the the salary (in thousands of dollars) of members of the two governing bodies t years since 2008.

Number of years and salaries of members of the two governing bodies

------------------------------------------------------------------------------------------------

Years since 2008 Salary (thousands of dollars)

------------------------------------------------------------------------------------------------

0 (2._) + ___

1 (2._) + ___

2 (2._) + ___

3 (2._) + ___

4 (2._) + ___

t ________

----------------------------------------------------------------------------------------------------

(b) Evaluate the expression that is found in part (a) for t = 5. What does the result means in this situation?

Answer: (a) The blank space inside the parenthesis is the number of years and the 2nd blank space is the salary: $167.2 thousand.

The last blank space is 2.t + 167.2.

(b) The value for t = 5 is 177.2 thousand.

Step-by-step explanation: The table in (a) is the description of the salaries per year. After 2008, there is an increase of 2000 per year.

Assuming t is in years, the expression for the salaries per year will be:

s = 2.t + 167.2

For part (b), t = 5. Substitute it into the equation, it is:

s = 2.t + 167.2

s = 2.5 + 167.2

s = 177.2

This means that in year 5, the salary will be $ 177.2 thousand.

4 0

3 years ago

Select correct answer

Sergio [31]

Answer:

The values of p in the equation are 0 and 6

Step-by-step explanation:

First, you have to make the denominators the same. to do that, first factor 2p^2-7p-4 = \left(2p+1\right)\left(p-4\right)2p

2

−7p−4=(2p+1)(p−4)

So then the equation looks like:

\frac{p}{2p+1}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{5}{p-4}

2p+1

p

−

(2p+1)(p−4)

2p

2

+5

=−

p−4

5

To make the denominators equal, multiply 2p+1 with p-4 and p-4 with 2p+1:

\frac{p^2-4p}{(2p+1)(p-4)}-\frac{2p^2+5}{(2p+1)(p-4)}=-\frac{10p+5}{(p-4)(2p+1)}

(2p+1)(p−4)

p

2

−4p

−

(2p+1)(p−4)

2p

2

+5

=−

(p−4)(2p+1)

10p+5

Since, this has an equal sign we 'get rid of' or 'forget' the denominator and only solve the numerator.

(p^2-4p)-(2p^2+5)=-(10p+5)(p

2

−4p)−(2p

2

+5)=−(10p+5)

Now, solve like a normal equation. Solve (p^2-4p)-(2p^2+5)(p

2

−4p)−(2p

2

+5) first:

(p^2-4p)-(2p^2+5)=-p^2-4p-5(p

2

−4p)−(2p

2

+5)=−p

2

−4p−5

-p^2-4p-5=-10p+5−p

2

−4p−5=−10p+5

Combine like terms:

-p^2-4p+0=-10p−p

2

−4p+0=−10p

-p^2+6p=0−p

2

+6p=0

Factor:

p=0, p=6p

7 0

2 years ago

Read 2 more answers

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago