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3 years ago

Rewrite the equation below so that it does not have fractions.

1 answer:

5 0

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What is the x-coordinate of the solution

Brut [27]

Answer:

x=-4

Step-by-step explanation:

3 0

3 years ago

△ABC ~ △DEF What is the scale factor between them?

VMariaS [17]

2/3

6x = 4
x = 2/3

The scale factor can be determined by using similar sides

3 0

3 years ago

The equation 6y = 30 - 8x has solutions of (b, 1) and (a, b).<br> What are the values of a and b?

victus00 [196]

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

In this question we need to solve the linear equation for each point, first for $(x,y) = (b, 1)$ and later for $(x,y) = (a, b)$ .

If we know that $(x,y) = (b, 1)$ , then the value of $b$ is:

$6 = 30-8\cdot b$

$8\cdot b = 24$

$b = 3$

If we know that $(x,y) = (a, b)$ and $b = 3$ , then the value of $a$ is:

$6\cdot b = 30 - 8\cdot a$

$18 = 30-8\cdot a$

$12 = 8\cdot a$

$a = \frac{3}{2}$

The values of $a$ and $b$ are $a = \frac{3}{2}$ and $b = 3$ , respectively.

To learn more on linear functions, we kindly invite to check this question: brainly.com/question/5101300

6 0

2 years ago

Tina is saving to buy a notebook computer. She has two options. The first option is to put $500 away initially and save $10 ever

Alexxandr [17]

Answer:

Tina would save the same amount using either option after 20 months.

With either option, Tina would save $700.

Step-by-step explanation:

This problem can be modeled by a first order equation:

Where Tina's saved money after n months is:

S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.

The first option is to put $500 away initially and save $10 every month, so:

$S_{1}(n) = 500 + 10n$

The second option is to put $100 away initially and save $30 every month, so:

$S_{2}(n) = 100 + 30n$

After how many months would Tina save the same amount using either option?

It will happen at the month n in which $S_{1}(n) = S_{2}(n)$ , so:

$S_{1}(n) = S_{2}(n)$

500 + 10n = 100 + 30n

500 - 100 = 30 - 10n

400 = 20n

20n = 400

$n = \frac{400}{20}$

n = 20.

Tina would save the same amount using either option after 20 months.

How much would she save with either option?

We can choose $S_{1}(20)$ or $S_{2}(20)$ , since they are equal

$S_{1}(20) = 500 + 10(20) = 500 + 200 = 700$

With either option, Tina would save $700.

3 0

3 years ago

A gift shop sells 140 wind chimes per month at $90 each. The owners estimate that for each $5 increase in price, they will sell

guapka [62]

Answer: $95

Step-by-step explanation:

Te new price will be 90 + 5x, if the price increases "x" times

The number of wind chimes sold per month will become 140 - 7x

$\begin{aligned}&\text {Revenue, } \mathrm{R}(\mathrm{x})=(90+5 \mathrm{x})(140-7 \mathrm{x}) \\&R^{\prime}(x)=5(140-7 x)-7(90+5 x) \\&R^{\prime}(x)=700-35 x-630-35 x \\&R^{\prime}(x)=70-70 x=0 \\&70 x=70 \\&x=1\end{aligned}$

Therefore, if the price becomes (90 + 5(1)) = $95 per wind chime, then the revenue will be maximum

6 0

3 years ago