1 year ago

Factorise: 27x^3 - 1/216 -9/2x^2 +1/4x

Mathematics

1 answer:

g100num [7]1 year ago

7 0

Answer:

Hello,

Step-by-step explanation:

$27x^3-\dfrac{9}{2}x^2+\dfrac{1}{4}x-\dfrac{1}{216} \\\\=(3x)^3-3*(3x)^2*\dfrac{1}{6} +3*(3x)*(\dfrac{1}{6} )^2-(\dfrac{1}{6} )^3\\\\=\boxed{(3x-\dfrac{1}{6} )^3}$

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