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Whitepunk [10]
3 years ago
14

Find the domain and range of the relation, and determine whether it is a function.

Mathematics
1 answer:
mina [271]3 years ago
7 0
The domain is all the x values so {2,-4, 1, 2, -1} 
The range is all the y values so    {1, 5, 7, -3, 2}

Yes, it is a function because each item in the domain matches one item in the ranges. 
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AlexFokin [52]

Given that:

Consider it is \sqrt{10} instead of 10 on two places.

\sqrt{10} is between 3  and 4. So, Beau thinks a good estimate for \sqrt{10} is = 3.5.

Solution:

To find \sqrt{10}, Beau found 3² = 9 and 4² = 16.

He said that since 10 is between 9 and 16.

Since 10 is close to 9, therefore \sqrt{10} must be close to 3. So, Beau's estimate is high.

Now,

(3.1)^2=9.61

(3.2)^2=10.24

Since, 10 lies between 9.61 and 10.24, therefore \sqrt{10} must be lies between 3.1 and 3.2.

\dfrac{3.1+3.2}{2}=3.15

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4 0
3 years ago
The ratio of students who wear glasses to the total number of students in the class is 2:5 if there are 14 students who wear gla
vazorg [7]

Answer:

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Step-by-step explanation:

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Now, there are 14 students how are wearing glasses.

We just times the whole Equation 1 by 7.

If there are 5 x 7 = 35 students in the class, then 2 x 7 = 14 of them would wear glasses and 3 x 7 = 21 of them wouldn't.

So, there are 35 students.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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