Answer:
bucket of water = 50.397 lbs
Step-by-step explanation:
Pi(r^2)(h) = volume
3.14(6^2)(12) = 1356.48 in^3 = volume of bucket
one ft^3 = 12 x 12 x 12 = 1728 in^3
1356.48/1728 = 0.785 ft^3 (volume of bucket)
0.785(64.2) = 50.397 lbs
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21+24
Just add 3 each time
Answer:
![7\sqrt[3]{x^2}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7Bx%5E2%7D)
Step-by-step explanation:
The rule of exponents that dictates this to be solved is:
![x^{\frac{a}{b}}=\sqrt[b]{x^a}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%7D%3D%5Csqrt%5Bb%5D%7Bx%5Ea%7D)
The power of 2/3 is on "x", NOT 7, so we use this property to write it as:
![x^{\frac{a}{b}}=\sqrt[b]{x^a} \\7x^{\frac{2}{3}}=7\sqrt[3]{x^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%7D%3D%5Csqrt%5Bb%5D%7Bx%5Ea%7D%20%5C%5C7x%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%3D7%5Csqrt%5B3%5D%7Bx%5E2%7D)
third answer choice is right, ![7\sqrt[3]{x^2}](https://tex.z-dn.net/?f=7%5Csqrt%5B3%5D%7Bx%5E2%7D)