Answer:
aₙ= 4n+11
Step-by-step explanation:
the sequence 15, 19, 23, 27
is AP with the first term 15 and
the common difference 19-15=23-19=27-23= 4
aₙ= a₁+(n-1)d
aₙ= 15+(n-1)*4= 15+4n- 4= 4n+11
aₙ= 4n+11
Im not sure wym but i think the answer is 20
Yes, they are all equal to each other
This is rationalising the denominator of an imaginary fraction. We want to remove all i's from the denominator.
To do this, we multiply the fraction by 1. However 1 can be expressed in an infinite number of ways. For example, 1 = 2/2 = 3/3 = 4n^2 / 4n^2 (assuming n is not zero!). Let's express 1 as the complex conjugate of the denominator, divided by the complex conjugate of the denominator.
The complex conjugate of (3 - 2i) is (3 + 2i). Then do what I just said:
4/(3-2i) * (3+2i)/(3+2i) = 4(3+2i)/(3-2i)(3+2i) = (12+8i)/(9-4i^2) = (12+8i)/(9+4) = (12+8i)/13
This is the answer you are looking for. I hope this helps :)
Answer: E
Step-by-step explanation:
4 divide 50 = 8 divide 2= 4
