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dimaraw [331]
2 years ago
14

How to graph f(x)=(x-2)^2+3

Mathematics
1 answer:
iris [78.8K]2 years ago
5 0

Using translation concepts, the graph of f(x) = (x - 2)² + 3 is given at the end of the question.

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

In this problem, we have that the parent and the translated function are given, respectively, by:

  • g(x) = x².
  • f(x) = (x - 2)² + 3.

The translations are as follows:

  • Right two units, as x -> x - 2.
  • Up 3 units, because f(x) = g(x) + 3.

Hence the graphs are given at the end of the answer, with the parent function in red and the translated function f(x) = (x - 2)² + 3 in green.

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

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andre [41]

Answer:

  f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}

Step-by-step explanation:

Each vertical asymptote corresponds to a zero in the denominator. When the function does not change sign from one side of the asymptote to the other, the factor has even degree. The vertical asymptote at x=-4 corresponds to a denominator factor of (x+4). The one at x=2 corresponds to a denominator factor of (x-2)², because the function does not change sign there.

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Each zero corresponds to a numerator factor that is zero at that point. Again, if the sign doesn't change either side of that zero, then the factor has even multiplicity. The zero at x=1 corresponds to a numerator factor of (x-1)².

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Each "hole" in the function corresponds to numerator and denominator factors that are equal and both zero at that point. The hole at x=-3 corresponds to numerator and denominator factors of (x-3).

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  \boxed{f(x)=\dfrac{(x+3)(x-1)^2}{(x+4)(x+3)(x-2)^2}}

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