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Mrac [35]
3 years ago
5

What is the range of this function? 543210

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0
7 is the range of this function
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The width of an extra large rectangle poster is 8 inches more than half its length.The area of this poster is 306 square inches
maria [59]

Answer:

a² + 16a - 612 = 0

Step-by-step explanation:

Here is the complete question :

The width of an extra large rectangle poster is 8 inches more than half its length. The area of this poster is 306 square inches

Write an equation in one variable that could be used to find the number of inches in the dimensions of this poster.

Area of a rectangle = length x width

Let length = a

width = 8 + 1/2a

Area =  (8 + 1/2a) x a

306 =  (8 + 1/2a) x a

multiply both sides of the equation by 2

612 = 16a + a²

a² + 16a - 612 = 0

the dimensions of the poster can be determined using quadratic formula

8 0
3 years ago
Pls help thanks i need this ty ty
Maurinko [17]

Answer:

31

Step-by-step explanation:

4 0
3 years ago
7.9x - 2 - 3.2x - 10 = 2.8 + x
inysia [295]

Answer:

x=4

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4 0
2 years ago
What is y=−7x+8 y=−7x−8 ​
Alenkasestr [34]

Answer:

these equations create graphs, explain what you need done

Step-by-step explanation:

8 0
3 years ago
Find the perimeter of ABC with vertices A (1,1), B (7,1), and C (1,9)
Effectus [21]

Answer:

24 unit

Step-by-step explanation:

Given,

The vertices of the triangle ABC are,

A (1,1), B (7,1), and C (1,9),

By the distance formula,

AB=\sqrt{(7-1)^2+(1-1)^2}=\sqrt{6^2}=6\text{ unit}

BC=\sqrt{(1-7)^2+(9-1)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10\text{ unit}

CA=\sqrt{(1-1)^2+(1-9)^2}=\sqrt{8^2}=8\text{ unit}

Thus, the perimeter of the triangle ABC = AB + BC + CA = 6 + 10 + 8 = 24 unit

4 0
3 years ago
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