V = (4/3) pi r^3
9. V = (4/3)(3.14)(7.62)^3 = 1852.4 meters^3
10. V = (4/3)(3.14)(33/2)^3 = 18,807.0 inches^3
11. V = (4/3)(3.14)(18.4/2)^3 = 3260.1 feet^3
12. V = (4/3)(3.14)(sqrt3)/2)^3 = 2.7 cm^3
13. C = 2*pi*r ; 24 = 2 * 3.14 * r; 24/6.28 = r ; r = 3.82
V = (4/3)(3.14)(3.82)^3 = 233.4 in^3
14.V = (4/3)(3.14)(35.8)^3 = 192,095.6 mm^3
I can't read # 15 but follow the steps above.
Answer:
what do you need help wth ?
Step-by-step explanation:
Answer:
a. P(X=50)= 0.36
b. P(X≤75) = 0.9
c. P(X>50)= 0.48
d. P(X<100) = 0.9
Step-by-step explanation:
The given data is
x 25 50 75 100 Total
P(x) 0.16 0.36 0.38 0.10 1.00
Where X is the variable and P(X) = probabililty of that variable.
From the above
a. P(X=50)= 0.36
We add the probabilities of the variable below and equal to 75
b. P(X≤75) = 0.16+ 0.36+ 0.38= 0.9
We find the probability of the variable greater than 50 and add it.
c. P(X>50)= 0.38+0.10= 0.48
It can be calculated in two ways. One is to subtract the probability of 100 from total probability of 1. And the other is to add the probabilities of all the variables less than 100 . Both would give the same answer.
d. P(X<100)= 1- P(X=100)= 1-0.1= 0.9
6. 5 shirts 20 minutes Multiply both by 3 to get to 60 minutes
15 shirts 60 minutes
15 shirts per hour
7. 250 miles + 50 miles = 300 miles
300 miles / 5 hours = 60 miles per hour
8. 360 pages / 12 hours = 30 pages per hour400 pages / 30 pages per hour = 13 1/3 hours
= 13 hours and 20 minutes
Answer:
<h3>#5</h3>
<u>Given vertices:</u>
These have same x-coordinate, so when connected form a vertical segment.
<u>The length of the segment is:</u>
The area of the rectangle is 72 square units, so the horizontal segment has the length of:
<u>Possible location of the remaining vertices (to the left from the given):</u>
and
<h3>#6</h3>
<u>Similarly to previous exercise:</u>
- (5, -8) and (5, 4) given with the area of 48 square units
<u>The distance between the given vertices:</u>
<u>The other side length is:</u>
<u>Possible location of the other vertices (to the right from the given):</u>
and
