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stepladder [879]
3 years ago
5

PLEASE Solve Fast |x+2|<4

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0
|x + 2| < 4
As neither x or 2 are negative, the bars do not matter and can be eliminated. 
x + 2 < 4
Minus 2 from both sides, and because you subtracted, make sure to turn the 'less than' sign into a 'greater than' sign.
x > 2 is your answer
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Answer:

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Step-by-step explanation:

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14=7y-21

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8 0
3 years ago
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Brrunno [24]

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Step-by-step explanation:

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4 years ago
brent went for a bycile ride the clocks shows the start time and the end time how long did he ride his bycile the start time is
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3 years ago
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gizmo_the_mogwai [7]

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Step-by-step explanation:

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3 years ago
Given that f(x) = 5x − 10 and g(x) = x + 3, solve for f(g(x)) when x = −1.
Oksi-84 [34.3K]
<span>f(x) = 5x − 10 and g(x) = x + 3

</span>f(g(x))  = 5(x + 3) − 10
f(g(x))  = 5x + 15 − 10
f(g(x))  = 5x + 5

when x = -1
f(g(-1))  = 5(-1) + 5
f(g(-1))  = - 5 + 5
f(g(-1))  = 0

Answer
<span>0</span>
8 0
3 years ago
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