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jenyasd209 [6]
3 years ago
9

Two-thirds of the students in Harry’s math class and three-fifths of the students in Amani’s math class are boys. Which question

about the classes is best modeled with a division expression?
A.If there are 12 boys, how many students are in Harry’s class?
B.If there are 24 students, how many boys are in Amani’s class?
C.What fraction of the students in Harry’s class are girls?
D.What fraction of the students in Amani’s class are honors students if the fraction is equal to mc013-1.jpg the fraction of students who are boys?
Mathematics
2 answers:
nata0808 [166]3 years ago
8 0
There are students in Harry's class. The fraction of girls in Harry's class is 1/3.

marissa [1.9K]3 years ago
5 0

Answer:

its c

Step-by-step explanation:

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Answer: The height of the mountain is 1,331.4 meters (approximately)

Step-by-step explanation: From the information given, the students were standing at point b which is 800 meters from the base of the mountain and the angle of elevation from that point is 59°. Assuming that the ground is level, we can derive a right angled triangle from this set of details and hence we have triangle ABC, where angle β is the reference angle, (59 degrees), BC is the distance from the students to the base of the mountain (800 meters) and the line AC is the height of the mountain.

The line AC is the opposite, since angle B is the reference angle, therefore we shall use the trigonometric ratio as follows;

Tan β = opposite/adjacent

Tan 59 = AC/800

Tan 59 x 800 = AC

1.6643 x 800 = AC

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Answer:

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Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

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Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

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