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Nastasia [14]
2 years ago
14

What is the value of 7(10 - 2^3) + 8 divided by 2

Mathematics
1 answer:
Zielflug [23.3K]2 years ago
5 0

7(10-2^3)+8 \div 2 \\ \\ 7(10-8)+8 \div 2 \\ \\ 7(2)+8 \div 2 \\ \\ 7(2)+4 \\ \\ 14+4 \\ \\ \boxed{18}

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How do you construct a frequency distribution table using sturge’s approximation
artcher [175]

The steps to use to construct a frequency distribution table using sturge’s approximation is as below.

<h3>How to construct a frequency distribution table?</h3>

The steps to construct a frequency distribution table using Sturge's approximation are as follows;

Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.

Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;

K = 1 + 3.322logN

where;

K= Number of classes

logN = Logarithm of the total number of observations.

Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size

Step 4; Locate the starting point: The lower class limit should take care of the smallest value in the raw data.

Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.

Step 6; Distribute the data into respective classes:

Read more about  frequency distribution table at; brainly.com/question/27820465

#SPJ1

6 0
2 years ago
HELP PLEASE! Write and solve the equation: The squares are identical. What is the area of each square?
Zarrin [17]

If a=4:

HOW TO FIND THE AREA

<h2>A=4a (formula)</h2>

A=4*4

A=16

If it's 100:

A=4*100

A=400

7 0
3 years ago
Read 2 more answers
Một ủy ban an toàn kiểm tra ngẫu nhiên 900 công nhân xây dựng trong thời gian làm việc, thấy có 48 công nhân không mang mũ bảo h
Usimov [2.4K]

Answer:

The percentage of workers not wearing the helmets is 5.3 %.

Step-by-step explanation:

A safety committee randomly examined 900 construction workers during their work, and found that 48 workers were not wearing helmets. Estimate the percentage of workers who do not wear protective masks during their working time with 98% confidence

total workers = 900

Not wearing helmet = 48

Percentage which are not wearing the helmets

= \frac{48}{900}\times 100 = 5.3 %%

6 0
3 years ago
B = 4 and c = -5, evaluate b 2 - c 2
NISA [10]

Hey!

-------------------------------------------------

Steps To Solve:

~Substitute

(4)2 - (-5)2

~Multiply

8 - (-10)

~Subtract

18

-------------------------------------------------

Answer:

18

-------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
Read 2 more answers
The number of major earthquakes in a year is approximately normally distributed with a mean of 20.8 and a standard deviation of
SCORPION-xisa [38]

Answer:

a) 51.60% probability that in a given year there will be less than 21 earthquakes.

b) 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 4.5

a) Find the probability that in a given year there will be less than 21 earthquakes.

This is the pvalue of Z when X = 21. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21 - 20.8}{4.5}

Z = 0.04

Z = 0.04 has a pvalue of 0.5160.

So there is a 51.60% probability that in a given year there will be less than 21 earthquakes.

b) Find the probability that in a given year there will be between 18 and 23 earthquakes.

This is the pvalue of Z when X = 23 subtracted by the pvalue of Z when X = 18. So:

X = 23

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 20.8}{4.5}

Z = 0.71

Z = 0.71 has a pvalue of 0.7611

X = 18

Z = \frac{X - \mu}{\sigma}

Z = \frac{18 - 20.8}{4.5}

Z = -0.62

Z = -0.62 has a pvalue of 0.2676

So there is a 0.7611 - 0.2676 = 0.4935 = 49.35% probability that in a given year there will be between 18 and 23 earthquakes.

5 0
3 years ago
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