Hello!
The letter D is in the place for the upper quartile
To find this you have to find the median of the data
List the numbers from least to greatest
12, 18, 34, 55, 59, 68, 80, 80
The medians are 55 and 59
To get the median we take the average of these numbers
55 + 59 = 114
114 / 2 = 57
The median is 57
To find the upper quartile you find the median of the numbers higher than 57
List the numbers that are higher than 57 in the data
59, 68, 80, 80
Take the average of 68 and 80
68 + 80 = 148
148/2 = 74
The answer is 74
Hope this helps!
W= width; L= length =w+22m; p= perimeter= 2(L+w)
1616 meters= 2 (L+w) substitute for L
1616m+ 2(w+22m+w) divide each side by 2
808m= 2w+22m subtract 22m from each side
786m=2w divide each side by 2
393m=w Anwer: The width is 393 meters
L=w+22m=393m+22m=415m Answer: The length is 415 meters
Answer:
(- 7, 4 )
Step-by-step explanation:
Given the 2 equations
5x + 3y = - 23 → (1)
y = 4 → (2)
Substitute y = 4 directly into (1_
5x + 3(4) = - 23, that is
5x + 12 = - 23 ( subtract 12 from both sides )
5x = - 35 ( divide both sides by 5 )
x = - 7
Solution is (- 7, 4 )
Answer:
2h 1' 1"
Step-by-step explanation:
1h = 1 hora
1' = 1 minute
1" = 1 secind
The sum of the three days is:
58' 45"
+ 40' 40"
20' 36"
= 118' 121"
118' 121" = 118' + 121"
1' = 60"
121" = 120" + 1" = (120/60) + 1 = 2' + 1"
Then:
118' + 121" = 118' + 2' ´+ 1" = 120' + 1"
1 h = 60'
(120/60) + 1 = 2h + 1'
then:
118' + 121" = 2h + 1' + 1"
= 2h 1' 1"
