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GalinKa [24]
1 year ago
8

Describe the relationship between the two quantities. volume of a cylinder; height

Mathematics
1 answer:
Temka [501]1 year ago
6 0

The volume of a  given cylinder is directly proportional to its height.

When determining the volume of a cylinder, we take;

=   Base Area(BA) of the cylinder * Height of the cylinder

This automatically proves that when the BA and Height of a particular cylinder is high, the results of its volume is also high.

<em>From the above statement, it is very correct to state that the </em><em>Height of a cylinder</em><em> is directly proportional to the </em><em>volume of a cylinder.</em>

<em></em>

It is also correct to state that the BA of a cylinder is directly proportional to the volume.

<u>Consider the image of the cylinder attached.</u>

Assuming we were to calculate the volume of water from different heights of the cylinder, for example;

Height1= 15 cm

Height2=10 cm

Radius=9 cm

V= \pi R^{2} * H

The volume of the different heights will be;

Height1=  \pi *  9^{2} * 15= 3, 818. 57 cm^{2}

Height2=  \pi *  9^{2} * 10= 2, 545. 71 cm^{2}

Hence the bigger height will result to bigger volume.

To find more on volume of cylinder, look into:

brainly.com/question/6204273

#SPJ4      

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Fifty draws are made at random with replacement from the box [ 0 0 1 1 1]. There are 33 ticket 1’s among the draws. The expected
Aleks04 [339]

Answer:

- The Expected value for the sum is 30.

- The Observed sum of 50 draws is 33.

- The Chance Error on the 50 draws is 3.

- The Standard Error on 50 draws is 2.191.

Step-by-step explanation:

The box contains [0, 0, 1, 1, 1]

Using probability to predict the expected outcome.

On one draw, the probability of drawing a 0 is (2/5).

And the probability of drawing a 1 is (3/5).

Probability mass function would look like

X | P(X)

0 | 0.40

1 | 0.60

So, expected value on one draw would be

E(X) = Σ xᵢpᵢ

xᵢ = each variable

pᵢ = probability of each variable

E(X) = (0×0.40) + (1×0.60) = 0.60.

Standard error on one draw = √[Σ(xᵢ - μ)²/N]

μ = E(X) = 0.60

Σ(xᵢ - μ)² = (0 - 0.60)² + (0 - 0.60)² + (1 - 0.6)² + (1 - 0.6)² + (1 - 0.6)² = 1.20

SE = √(1.2/5) = 0.490

So, for 50 draws (with replacement),

E(50X) = 50E(X) = 50 × 0.60 = 30.

For 50 draws, standard error = √50 × 0.490 = 2.191

The expected value for the sum = 30

The observed valued for the sum = (33×1) + (17×0) = 33

Chance Error = (Observed Outcome) - (Expected Outcome) = 33 - 30 = 3

Standard error gives an idea of how large the chance error would be.

Standard error on 50 draws = 2.191

Hope this Helps!!!

5 0
3 years ago
For each statement below enter a T (true) the statement is true and an F (false) otherwise. In this problem you need to get ever
aleksley [76]

Answer:

T

T

T

T

T

T

F

Step-by-step explanation:

3 0
2 years ago
Area of rectangle 2x8/9
Vikki [24]

Answer:

32/9

Step-by-step explanation:

2*(2)(8/9) = 4*8/9 = 32/9

3 0
2 years ago
Intr un album numarul de fotografii s a micsorat cu 50%. Cu cat trebuie sa se mareasca pentru a reveni la numarul initial? Raspu
hodyreva [135]

Răspuns:

100%

Explicație pas cu pas:

Permiteți numărul inițial de fotografii = x

x - 50% din x = x - 0,5x = 0,5x

0,5x + câte% din 0,5x = x

x - 0,5x = y% de 0,5x

0,5x / 0,5x = 1

Prin urmare,

100% = 1

Prin urmare, x trebuie mărit cu 100% pentru a reveni la numărul original.

3 0
2 years ago
The recycling center pays $0.01 for each aluminum can recycled. Dan was payed $10.00 for all his aluminum cans. How many aluminu
Setler [38]

Answer:

1000

Step-by-step explanation:

To solve this you divide 10/0.01 and you get 1000.

Hope it helps!

8 0
3 years ago
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