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Burka [1]
3 years ago
11

What is the length of AB? Round your answer to the nearest

Mathematics
1 answer:
const2013 [10]3 years ago
8 0
23’3 because I went over the test and I got it correct I’m pretty sure (sorry if I’m wrong I just went with the internet :()
You might be interested in
Please help with this question
aleksandr82 [10.1K]

Answer:

D) -9/4

Step-by-step explanation:

please refer to the picture I sent

5 0
3 years ago
PLEASE HELP ME!<br> I have to find the measurement of the angle but i can't figure it out.
Vadim26 [7]

<u>Answer:</u>

  • The value of ∠TMV is 45°.

<u>Step-by-step explanation:</u>

<u>We know that:</u>

  • ∠VTM + ∠TMV + ∠MVT = 180°
  • ∠VTM = 92
  • ∠MVT = 43

<u>Work:</u>

  • ∠VTM + ∠TMV + ∠MVT = 180°
  • => 92 + 43 + ∠TMV = 180°
  • => 135 + ∠TMV = 180°
  • => ∠TMV = 180 - 135
  • => ∠TMV = 45°

Hence, <u>the value of ∠TMV is 45°.</u>

Hoped this helped.

BrainiacUser1357

3 0
3 years ago
The term 3x2 in the quotient is the result of dividing 3x4 by
earnstyle [38]

Answer:

x^{2}

Step-by-step explanation:

Let

n------> the denominator of the quotient

we know that

\frac{3x^{4}}{n}=3x^{2}

Solve for n

n=\frac{3x^{4}}{3x^{2}}

n=x^{2}

6 0
3 years ago
Read 2 more answers
14. Find three equivalent expressions for 6x+3
posledela
(0,3)
(1,9)
(2,15)
Here are three equivalent expressions

6 0
3 years ago
Help please!!!(will mark brainliest)
Pani-rosa [81]

Step-by-step explanation:

remember, a probability is always desired cases over total possible cases.

the class has 10+15 = 25 students.

and 5 of them will be picked as representatives to the school board.

how many total possibilities do we have ?

since picked students can be picked only once, and the sequence of the 5 picked students in the group does not matter, we have a combination without repetition :

C(25, 5) = 25! / (5! × (25-5)!) = 25! / (5! × 20!) =

= 25×24×23×22×21 / (5×4×3×2) =

= 5×1×23×22×21 = 53,130 possible outcomes.

how many desired outcomes ?

that would be how many options we have to pick 2 out of 10 and 3 out of 15 :

C(10,2) × C(15,3) = 10! / (2 × 8!) × 15! / (3! × 12!) =

= 10×9/2 × 15×14×13/(3×2) =

= 5×9 × 5×7×13 = 20,475 desired outcomes

and the probability is

20475 / 53130 = 4095 / 10626 = 1365 / 3542 = 195 / 506

= 0.385375494... ≈ 0.39

5 0
2 years ago
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