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I am Lyosha [343]
2 years ago
8

What subnet mask can be used to segment the 172.16.0.0 network to allow for a minimum of 6 subnets while maximizing the number o

f hosts per subnet?
Computers and Technology
1 answer:
marishachu [46]2 years ago
5 0

The subnet mask can be utilized to segment the 172.16.0.0 network to qualify for a minimum of 6 subnets while maximizing the numeral of broadcasters per subnet is 255.255.224.0

<h3>What do subnet masks mean?</h3>
  • A subnet mask is a 32-bit numeral formed by setting keeper bits to all 0s and developing network times to all 1s.
  • In this way, the subnet mask divides the IP speech into the network and host addresses.
  • A subnet mask is used to separate an IP address into two pieces. One element defines the host (computer), and the different part identifies the network to which it belongs.
  • To better comprehend how IP lessons and subnet masks work, look at an IP speech and see how it's managed.

To learn more about  subnet mask, refer to:

brainly.com/question/3234986

#SPJ4

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<h3>HOPE THIS ANSWER IS HELPFUL TO U :)</h3>
4 0
3 years ago
Suppose users share a 1-Gbps link. Also, suppose each user requires 200 Mbps when transmitting, but each user only transmits 30
V125BC [204]

Answer:

The answer is "5 users and 1 block".

Explanation:

In Option a:

Bandwidth total = 1-Gbps \times 1000

                          = 1,000 \ Mbps      

Any User Requirement = 200 \ Mbps

The method for calculating the number of approved users also is:  

Now, calculate the price of each person for overall bandwidth and demands,  

\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}

                                     =\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users

In Option b:

\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}

\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}

                                = \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\

mean user = 25 \times \frac{1}{20} \\\\

                  = 1.25

max user = \frac{10^9}{40 \times 10^6} \\\\

                = \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\

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