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Mrrafil [7]
3 years ago
14

After class, Anita and Bev make plans to study for their psychology exam together but cannot decide on a time or location. In ad

dition, Anita realizes that she left her phone in her apartment. Anita and Bev change their mind and agree that it is easiest simply to meet at Bev's dorm. Bev gives Anita her room number and passcode. Anita likely will be able to retain this information in short-term memory, without additional processing, for:_________.a. a second or lessb. 30 seconds or lessc. about two minutesd. a maximum of five minutes
Computers and Technology
1 answer:
Paladinen [302]3 years ago
8 0

Answer:

Option B; 30 SECONDS OR LESS.

Explanation:

Short-term memory, also known as primary or active memory, is the information we are currently aware of or thinking about.

When short-term memories are not rehearsed or actively maintained, they last mere seconds.

Most of the information kept in short-term memory will be stored for less than 30 seconds (approximately 20 to 30 seconds), but it can be just seconds if rehearsal or active maintenance of the information is not done.

Therefore, Anita likely will be able to retain the information in short-term memory, without additional processing, for 30 SECONDS OR LESS.

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Answer:

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Explanation:

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4 0
2 years ago
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What are the benefits of a relationship in RDBMS <br>​
natali 33 [55]

Answer:

To sum up all the advantages of using the relational database over any other type of database, a relational database helps in maintaining the data integrity, data accuracy, reduces data redundancy to minimum or zero, data scalability, data flexibility and facilitates makes it easy to implement security methods.

Explanation:

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4 0
2 years ago
For this problem, you will write a function standard_deviation that takes a list whose elements are numbers (they may be floats
Evgesh-ka [11]

Answer:

  1. import math  
  2. def standard_deviation(aList):
  3.    sum = 0
  4.    for x in aList:
  5.        sum += x  
  6.    
  7.    mean = sum / float(len(aList))
  8.    sumDe = 0
  9.    for x in aList:
  10.        sumDe += (x - mean) * (x - mean)
  11.    
  12.    variance = sumDe / float(len(aList))
  13.    SD = math.sqrt(variance)
  14.    return SD  
  15. print(standard_deviation([3,6, 7, 9, 12, 17]))

Explanation:

The solution code is written in Python 3.

Firstly, we need to import math module (Line 1).

Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).

We can test the function using a sample list (Line 20) and we shall get 4.509249752822894

If we pass an empty list, a ZeroDivisionError exception will be raised.

3 0
3 years ago
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
What is local area network​
otez555 [7]

Explanation:

local area network is a computer network that interconnects computers within a limited area such as a residence, school, laboratory, university campus or office building. By contrast, a wide area network not only covers a larger geographic distance, but also generally involves leased telecommunication circuits.

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3 0
3 years ago
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