The answer is A county-based correctional system. The most common type of local correction system is a county-based correctional system.
Answer:
The new root will be 2.
<em></em>
Explanation:
The binary tree is not properly presented (See attachment)
To answer this; first, we need to order the nodes of the tree in a pre-order traversal.
We use pre-order because the question says if something is removed from the left child.
So, the nodes in pre-order form is: 14, 2, 1, 5, 4, 16.
The root of the binary tree is 14 and if 14 is removed, the next is 2.
<em>Hence, the new root will be 2.</em>
Answer:
Explanation:
a)use order by clause for sorting
for $x in doc("books.xml")/bib/book order by xs:float($x/price) return $x/title (default sorted in ascending order)
or
for $x in doc("books.xml")/bib/book order by xs:float($b/price) descending return $b/title (sorted in descending order)
b)doc("books.xml")//book[author = 'Abiteboul']
c)for $x in distinct-values(doc("bib.xml")/bib/book/author)
return <res>
<name>{$x}</name>
<count>
{count (doc("bib.xml")//book[exists(indexof(author,$x))]) }
</count>
<res>
Answer:
You would put the cursor after the letter v in vermont and press back space and type a capital V to make it Vermont.
Answer:
PROGRAM QuadraticEquation
Solver
IMPLICIT NONE
REAL :: a, b, c
;
REA :: d
;
REAL :: root1, root2
;
//read in the coefficients a, b and c
READ(*,*) a, b, c
WRITE(*,*) 'a = ', a
WRITE(*,*) 'b = ', b
WRITE(*,*) 'c = ', c
WRITE(*,*)
// computing the square root of discriminant d
d = b*b - 4.0*a*c
IF (d >= 0.0) THEN //checking if it is solvable?
d = SQRT(d)
root1 = (-b + d)/(2.0*a) // first root
root2 = (-b - d)/(2.0*a) // second root
WRITE(*,*) 'Roots are ', root1, ' and ', root2
ELSE //complex roots
WRITE(*,*) 'There is no real roots!'
WRITE(*,*) 'Discriminant = ', d
END IF
END PROGRAM QuadraticEquationSolver