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sweet [91]
1 year ago
12

A musical phrase does not necessarily need to have a sense of completion in and of itself.

SAT
1 answer:
Setler79 [48]1 year ago
4 0

It is true that a musical phrase does not necessarily need to have a sense of completion in and of itself.

A cadence, a type of musical punctuation, marks the end of a phrase, which is a substantial musical concept. Through the interaction of melody, harmony, and rhythm, phrases are produced in music.

From linguistic grammar, terms like sentence and verse have been included into the language of music.

Despite frequent comparisons between the musical and linguistic expressions, this term "is one of the most ambiguous in music, there is no consistency in applying these terms and cannot be only with melodies of a very simple type, especially those of some dances, can the terms be used with some consistency."

Learn more about Musical Phrase here

brainly.com/question/5707756

#SPJ4

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Answer:

As Lincoln opens his speech with an allusion to the Declaration, he closes it with an allusion to the Constitution. The Preamble to the Constitution begins with the words "We the people." By using "the people," Lincoln alludes to that crucial document.

Explanation:

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According to the partnership of 21st century learning critical thinking ability includes all of the following skills except solve problems. 

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Use series to approximate the definite integral i to within the indicated accuracy. i = 1/2 x3 arctan(x) dx 0 (four decimal plac
Valentin [98]

The expression \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx  is an illustration of definite integrals

The approximated value of the definite integral is 0.0059

<h3>How to evaluate the definite integral?</h3>

The definite integral is given as:

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx

For arctan(x), we have the following series equation:

\arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}

Multiply both sides of the equation by x^3.

So, we have:

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}  * x^3

Apply the law of indices

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1 + 3}}{2n + 1}}

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Evaluate the product

x^3 \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Introduce the integral sign to the equation

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =\int\limits^{1/2}_{0} \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Integrate the right hand side

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}} ]\limits^{1/2}_{0}

Expand the equation by substituting 1/2 and 0 for x

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - [ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{0^{2n + 4}}{2n + 1}} ]

Evaluate the power

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - 0

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}}

The nth term of the series is then represented as:

T_n = \frac{(-1)^n}{2^{2n + 5} * (2n + 4)(2n + 1)}

Solve the series by setting n = 0, 1, 2, 3 ..........

T_0 = \frac{(-1)^0}{2^{2(0) + 5} * (2(0) + 4)(2(0) + 1)} = \frac{1}{2^5 * 4 * 1} = 0.00625

T_1 = \frac{(-1)^1}{2^{2(1) + 5} * (2(1) + 4)(2(1) + 1)} = \frac{-1}{2^7 * 6 * 3} = -0.0003720238

T_2 = \frac{(-1)^2}{2^{2(2) + 5} * (2(2) + 4)(2(2) + 1)} = \frac{1}{2^9 * 8 * 5} = 0.00004340277

T_3 = \frac{(-1)^3}{2^{2(3) + 5} * (2(3) + 4)(2(3) + 1)} = \frac{-1}{2^{11} * 10 * 7} = -0.00000634131

..............

At n = 2, we can see that the value of the series has 4 zeros before the first non-zero digit

This means that we add the terms before n = 2

This means that the value of \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx to 4 decimal points is

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.00625 - 0.0003720238

Evaluate the difference

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0058779762

Approximate to four decimal places

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0059

Hence, the approximated value of the definite integral is 0.0059

Read more about definite integrals at:

brainly.com/question/15127807

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Explanation:

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