Based on the calculations, the pressure inside this droplet is equal to 2,909.35 kPa.
<u>Given the following data:</u>
- Surface tension = 0.00518 lbf/ft to N/m = 0.00702 N/m.
- Atmospheric pressure = 14.7psia to kPa = 101.35 kPa.
- Diameter = 0.01 mm to m = 0.00001 m.
Radius, r = 
= 0.000005 m.
<h3>How to determine the pressure inside a droplet.</h3>
For a droplet with only one surface, its pressure is given by this formula:
Substituting the given parameters into the formula, we have;
Inside pressure = 2,909.35 kPa.
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The right answers is option c
Answer:
The answer is false because the center of gravity contributes greatly to the individual stability of a person or thing. The center of gravity is the center of mass of an object and therefore by raising or lowering that point, of gravity, you can cause an object or person to lose stability very quickly.
Explanation:
How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
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