THAT IS THE ANSWER 1)requires the new programmers to insert comments o their own
Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
The answer is copyright like for example if you copy and paste a essay offline and don’t give credit to the author it called copyright
Answer:
The answer is "5.5 and 90.90%"
Explanation:
For point 1:
To calculate the speed from fast mode, its run time without enhancement should be worked out. Designers are aware of which two selves are implicated throughout the accelerated project planning: the empty () and the increased stages ().
Although not enhanced, this would take almost as long () and for the combine to give phase; even so, the increased phase would've been 10 times longer, as well as . Thus the corresponding total speed without enhancement is
Its overall speed is:
For point 2:
We re-connect these figures in Amdahl's Law throughout order to identify how long it would take for both the initial implementation:
Answer:
Tabs
Explanation:
The ribbon contains the tabs. The tabs contain the command groups which hold commands
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