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Lyrx [107]
3 years ago
14

What aspects of your life are most influenced by media and technology​

Computers and Technology
1 answer:
Anastasy [175]3 years ago
5 0

Answer:

Everyday life

Explanation:

Television

office work (computers )

Music

video games

ware house work uses technology

work from home jobs use technology

cellular towers

You might be interested in
Input 10 integers and display the following:
LekaFEV [45]

Answer:

// code in C++

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

   // variables

   int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;

   int largest=INT_MIN;

   int smallest=INT_MAX;

   int n;

   cout<<"Enter 10 Integers:";

   // read 10 Integers

   for(int a=0;a<10;a++)

   {

       cin>>n;

       // find largest

       if(n>largest)

       largest=n;

       // find smallest

       if(n<smallest)

       smallest=n;

       // if input is even

       if(n%2==0)

       {  

           // sum of even

           sum_even+=n;

           // even count

           eve_count++;

       }

       else

       {

           // sum of odd    

          sum_odd+=n;

          // odd count

          odd_count++;

       }

   }

   

   // print sum of even

   cout<<"Sum of all even numbers is: "<<sum_even<<endl;

   // print sum of odd

   cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;

   // print largest

   cout<<"largest Integer is: "<<largest<<endl;

   // print smallest

   cout<<"smallest Integer is: "<<smallest<<endl;

   // print even count

   cout<<"count of even number is: "<<eve_count<<endl;

   // print odd cout

   cout<<"count of odd number is: "<<odd_count<<endl;

return 0;

}

Explanation:

Read an integer from user.If the input is greater that largest then update the  largest.If the input is smaller than smallest then update the smallest.Then check  if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.

Output:

Enter 10 Integers:1 3 4  2 10 11 12 44 5 20                                                                                

Sum of all even numbers is: 92                                                                                            

Sum of all odd numbers is: 20                                                                                              

largest Integer is: 44                                                                                                    

smallest Integer is: 1                                                                                                    

count of even number is: 6                                                                                                

count of odd number is: 4

3 0
3 years ago
Write a program that converts a number entered in Roman numerals to decimal. your program should consist of a class, say, Roman.
arlik [135]

Answer:

The code is given below in Java with appropriate comments

Explanation:

import java.util.*;

public class RomantoDecimal {

    public static void main(String[] args)

    {

         Scanner SC = new Scanner(System.in);

         RomantoDecimal r = new RomantoDecimal();

         System.out.println("Enter a Roman number :");

         // INPUT A ROMAN NUMBER

         String rNum = SC.next();

         // CALL convertToDecimal FOR CONVERSION OF ROMAN TO DECIMAL

         r.convertToDecimal(rNum);

    }

    // M=1000, D=500, C=100, L=50, X=10, V=5, I=1

    public void convertToDecimal(String roamNo)

    {

         int number = 0;

         // TEACK EACH DIGIT IN THE GIVEN NUMBER IN REVERSE ORDER

         for (int i = roamNo.length() - 1; i >= 0; i--)

         {

             // FIND OUT WHETHER IT IS 'M' OR NOT

             if (roamNo.charAt(i) == 'M')

             {

                  if (i != 0)

                  { // CHECK WHETHER THERE IS C BEFORE M

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 900;

                            i--;

                            continue;

                       }

                  }

                  number = number + 1000;

             }

             // FIND OUT WHETHER IT IS 'D' OR NOT

             else if (roamNo.charAt(i) == 'D')

             {

                  if (i != 0)

                  {

                  // CHECK WHETHER THERE IS C BEFORE D

                       if (roamNo.charAt(i - 1) == 'C')

                       {

                            number = number + 400;

                            i--;

                            continue;

                       }

                 }

                  number = number + 500;

             }

            // FIND OUT WHETHER IT IS 'C' OR NOT

             else if (roamNo.charAt(i) == 'C')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'X')

                       {

                            number = number + 90;

                            i--;

                            continue;

                      }

                  }

                  number = number + 100;

             }

             else if (roamNo.charAt(i) == 'L')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i) == 'X')

                       {

                            number = number + 40;

                            i--;

                            continue;

                       }

                  }

                  number = number + 50;

             }

             // FIND OUT WHETHER IT IS 'X' OR NOT

             else if (roamNo.charAt(i) == 'X')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 9;

                            i--;

                            continue;

                       }

                  }

                  number = number + 10;

             }

             // FIND OUT WHETHER IT IS 'V' OR NOT

             else if (roamNo.charAt(i) == 'V')

             {

                  if (i != 0)

                  {

                       if (roamNo.charAt(i - 1) == 'I')

                       {

                            number = number + 4;

                            i--;

                            continue;

                       }

                  }

                  number = number + 5;

             }

            else // FIND OUT WHETHER IT IS 'I' OR NOT

             {

                  number = number + 1;

             }

         }// end for loop

         System.out.println("Roman number: " + roamNo + "\nIts Decimal Equivalent: " + number);

    }

}

3 0
3 years ago
Windows OS and Mac OS are examples of which type of operating system?
german
Windows OS and Mac OS are examples of single user, multi tasking Operating Systems.
5 0
3 years ago
Read 2 more answers
Can Sombody please help me with this question, I'm struggling!
hjlf

Answer:

umm let me check if my answer is right

Explanation:

3 0
3 years ago
Write a program in Java programming language that given two clock times prints out the absolute number of minutes between them
Triss [41]

Answer:

// Java Program to Find the difference

// between Two Time Periods

// Importing the Date Class from the util package

import java.util.*;

// Importing the SimpleDateFormat

// Class from the text package

import java.text.*;

public class GFG {

public static void main(String[] args) throws Exception

{

 // Dates to be parsed

 String time1 = "18:00:00";

 String time2 = "7:30:50";

 // Creating a SimpleDateFormat object

 // to parse time in the format HH:MM:SS

 SimpleDateFormat simpleDateFormat

  = new SimpleDateFormat("HH:mm:ss");

 // Parsing the Time Period

 Date date1 = simpleDateFormat.parse(time1);

 Date date2 = simpleDateFormat.parse(time2);

 // Calculating the difference in milliseconds

 long differenceInMilliSeconds

  = Math.abs(date2.getTime() - date1.getTime());

 // Calculating the difference in Hours

 long differenceInHours

  = (differenceInMilliSeconds / (60 * 60 * 1000))

  % 24;

 // Calculating the difference in Minutes

 long differenceInMinutes

  = (differenceInMilliSeconds / (60 * 1000)) % 60;

 // Calculating the difference in Seconds

 long differenceInSeconds

  = (differenceInMilliSeconds / 1000) % 60;

 // Printing the answer

 System.out.println(

  "Difference is " + differenceInHours + " hours "

  + differenceInMinutes + " minutes "

  + differenceInSeconds + " Seconds. ");

}

}

7 0
2 years ago
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