Question

50 people were asked if they speak French or German or Spanish. Of these people, 31 speak French, 2 speak French, German and Spanish. 4 speak French and spanish but no German. 7 speak German and spanish. 8 speak any of the languages all 10 people who speak German speak at least one other language. Two of the 50 people are chosen at random. Work out the probability that they both only speak Spanish

Answer 1

The probability that they both only speak Spanish is P = 0.005

How to find the probability?

There are 50 people.

We know that:

• 31 of these speak French.
• 2 speak French, German, and Spanish.
• 4 speak French and Spanish.
• 7 speak German and Spanish.
• 8 speak any of the lenguages.
• 10 speak german (and also other lenguages).

Then, the number that speaks only Spanish is:

50 - (31 + 10 + 8 - 3) = 4

(this is, the total number of people minus the ones that speak the other (or neither) lenguages, the "-3" appears there because 3 of the ones that speak German also speak French)

Then the probability that the first randomly selected person speaks Spanish is equal to the quotient between the number that speaks Spanish and the total number:

p = 4/50

For the next person we compute the probability in the same way, but this time there are 3 people that talk Spanish and 49 people in total:

q = 3/49

The joint probability is the product of the two individual ones:

P = (4/50)*(3/49) = 0.005

If you want to learn more about probability:

brainly.com/question/25870256

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