Which figures demonstrate a single reflection? Select each correct answer.

Mathematics

1 answer:

AysviL [449]2 years ago

5 0

Answer:

Please see the attached image below, to find more information about the graph

The figures that are obtained by a single reflection are shown in the image inside a red rectangle.

The axis of reflection is shown with a black line.

- The figure from the left shows horizontal reflection

- The figure from the right shows vertical reflection

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Find the are of a parallelogram that has a base of 7 1/2 and a height of 5 2/7

Amiraneli [1.4K]

Use the formula for the area of a parallelogram:

$\sf A=bh$

Plug in what we know:

$\sf A=(7\dfrac{1}{2})(5\dfrac{2}{7})$

Convert both of them into improper fractions. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

$\sf A=(\dfrac{15}{2})(\dfrac{37}{7})$

Now multiply the numerators and denominators together:

$\sf A=\dfrac{15}{2}\cdot\dfrac{37}{7}\rightarrow\dfrac{15\cdot 37}{2\cdot 7}\rightarrow\dfrac{555}{14}$

Convert it back into a mixed number. 14 goes into 555 thirty-nine times. 14 * 39 = 546. 555 - 546 = 9. So we have 39 wholes and 9 left over, or:

$\sf 39\dfrac{9}{14}$

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2 years ago

Simplify the expression by combining like terms. -8y + 2 + 10y - 7<br> Please help

Alecsey [184]

Answer:

<u>2y - 5 (read below)</u>

Step-by-step explanation:

-8y + 10y = 2y

2 + (-7) = -5

Your expression could/would be:

2y - 5.

Hope this helps!