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1 year ago

3x + 2.3 = 11.6 help please

Mathematics

2 answers:

Zielflug [23.3K]1 year ago

6 0

Solution:

$x=3.1$

Hope this helps!

Vilka [71]1 year ago

6 0

Answer:

x = 3.1

Step-by-step explanation:

3x + 2.3 = 11.6

3x = 11.6 - 2.3

3x = 9.3

x = 9.3/3

x = 3.1

Check:

3*3.1 + 2.3 = 11.6

9.3 + 2.3 = 11.6

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Simplify the expression (2^3)^-2

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1/64

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Whats answere y+2=-3 (x - 4)

faust18 [17]

Answer:

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Step-by-step explanation:

Slope is defined as the change in y divided by the change in x. We note that for x=0, the value of y is -10.000 and for x=2.000, the value of y is -4.000. So, for a change of 2.000 in x (The change in x is sometimes referred to as "RUN") we get a change of -4.000 - (-10.000) = 6.000 in y. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN)

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2 years ago

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Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf

kobusy [5.1K]

Answer:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We have the following data given:

$\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by $\alpha=1-0.93=0.07$ and $\alpha/2 =0.035$ . And the critical value would be given by:

$z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811$

The confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}$

And replacing we got:

$(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903$

$(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097$

And the confidence interval for the difference of means would be given by:

$0.2903 \leq \mu_1 -\mu_2 \leq 0.5097$

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2 years ago

Help plz know what you are doing!!!!!

andre [41]

Hey!
1. scalene
2. isosoles
7. scalene
8. scalene
5. isosoles
6. isosoles
7. scalene
8. equilateral

5 0

2 years ago

Can someone explain how these equal 5 and -5 please

uysha [10]

I'm not sure how you obtained -5 as your answer but this is the mathematical explanation. hope this helps!
${x}^{2} + 3x = 40 \\ {x}^{2} + 3x - 40 = 0 \\(x + 8)(x - 5) = 0 \\ x = - 8 \\ x = 5$

6 0

3 years ago