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3 years ago

Solving equations-variables on both sides!

Mathematics

1 answer:

scZoUnD [109]3 years ago

5 0

Simplifying

64 + -12w = 6w

Solving

64 + -12w = 6w

Solving for variable 'w'.

Move all terms containing w to the left, all other terms to the right.

Add '-6w' to each side of the equation.

64 + -12w + -6w = 6w + -6w

Combine like terms: -12w + -6w = -18w

64 + -18w = 6w + -6w

Combine like terms: 6w + -6w = 0

64 + -18w = 0

Add '-64' to each side of the equation.

64 + -64 + -18w = 0 + -64

Combine like terms: 64 + -64 = 0

0 + -18w = 0 + -64

-18w = 0 + -64

Combine like terms: 0 + -64 = -64

-18w = -64

Divide each side by '-18'.

w = 3.555555556

Simplifying

w = 3.555555556

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Use the function f(x) = x2 − 2x 8 and the graph of g(x) to determine the difference between the maximum value of g(x) and the mi

slamgirl [31]

The difference between the maximum value of g(x) and the minimum value of f(x) is 5.

Given function is:

$f(x)=x^{2} -2x+8$ ......(1)

<h3>What is the general form of a quadratic equation?</h3>

The general form of a quadratic equation is $ax^{2} +bx+c=0$ with $a\neq 0$ .

As we know the minimum value of a quadratic function is $\frac{4ac-b^{2} }{4a}$ when a>0

For f(x) a>0 so minimum value of f(x) = $\frac{4*1*8-(-2)^2}{4*1}$ =7

From the graph, the maximum value of g(x) =12

So, the difference between the maximum value of g(x) and the minimum value of f(x) =12-7 =5

Hence, the difference between the maximum value of g(x) and the minimum value of f(x) is 5.

To get more about quadratic functions visit:

brainly.com/question/1214333

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2 years ago

Round to the nearest thousands<br> 3475.6993

Andreyy89

3475.699

°°°°°°°°°°°°°°°

Am I correct?

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3 years ago

Jim’s dog weighs 18 pounds 10 ounces. His cat weighs 6 pounds 3 ounces. How many more ounces does Jim’s dog weigh than his cat?

JulijaS [17]

The dog weighs 99 ounces more than the cat. you just have to convert to ounces then subtract.

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3 years ago

Read 2 more answers

For what interval is the function f(x) = (20 + \sqrt{x}) / (\sqrt{20 + x}) continuous?

konstantin123 [22]

Try this solution:
1. according to the condition
$\left \{ {{x \geq 0} \atop {20+x\ \textgreater \ 0}} \right. \ =\ \textgreater \ \ x \geq 0.$
2. for more details see the attached graph.

Answer: [0;+oo)

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3 years ago

Square root of 4×-1=5

borishaifa [10]

Answer:3/2

how i did this

 Add 11 to both sides.

4x=5+1

Simplify 5+15+1 to 66.

4x=6

Divide both sides by 4

x= 6/4

Simplify 6/4 to 3/2

Awnser

x=3/2

Sorry if not helpful just trying my best :)

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3 years ago