Composite because number that are greater than 5 are composite
2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
f(3)=56, f(-4)=277
Step-by-step explanation:
f(x)=x^4-8x-11
f(3)=3^4-8(3)-11=3*3*3*3-24-11=9*3*3-35=27*3-25=81-25=56
f(-4)=(-4)^4-8(-4)-11=(-4)(-4)(-4)(-4)+32-11=(16)(16)+32-11=256+32-11=288-11=277
The estimated distance is 1,000 for each trip....the exact distance is 1,075.
When dividing fractions these are the steps you will take:
1. The first number in the expression stays the same. If it is a whole number then you may just place a one in the denominator and keep the numerator as the whole number like so:
÷ 
2. Change the division sign into a multiplication sign
×
3. Take the reciprocal (switch the places of numerator and denominator) of the second number in the expression
× 
4. Multiply across
^^^This can be further simplified:
4
Hope this helped!
~Just a girl in love with Shawn Mendes
