1 year ago

Help pls I don’t know anything

Mathematics

1 answer:

prohojiy [21]1 year ago

6 0

Answer:

Step-by-step explanation:

first do this

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Factor: 128 + 2d^3 <br><br> cubes lol

BARSIC [14]

The factorization if the given expression 128 + 2d³ is 2(64 + d³).

<h3>Factorization</h3>

128 + 2d³

There are two parameters in the expression;

128
2d³

The common factors between 128 and 2d³ is 2

So,

128 + 2d³

= 2(64 + d³)

Learn more about factorization:

brainly.com/question/25829061

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marin [14]

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2 years ago

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(x-1)^2+(2-x)^2-3(x-5)*(x-5)

Natali5045456 [20]

Answer:

$-x^2+24x-70$

Step-by-step explanation:

$(x-1)^2+(2-x)^2-3(x-5)*(x-5)\\=> (x - 1)^2 + (2 - x)^2 - 3(x - 5)^2\\=> x^2 - 2x + 1 + 4 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 2x + 5 - 4x + x^2 - 3(x - 5)^2\\=> x^2 - 6x + 5 + x^2 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x - 5)^2\\=> 2x^2 - 6x+5 - 3(x^2 - 10x + 25)\\=> 2x^2 - 6x+5 - 3x^2+30x-75\\=> -x^2 - 6x + 5 + 30x - 75\\=> -x^2 + 24x + 5-75\\=> -x^2+24x-70$