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Lana71 [14]
3 years ago
13

Multiply a number n by 5, and then add 3 to product

Mathematics
1 answer:
joja [24]3 years ago
4 0

Answer:

5n+3

Step-by-step explanation:

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The​ ____ is another term for the arithmetic average.
antiseptic1488 [7]

The answer is the mean.

"For a data set, the arithmetic mean, also called the mathematical expectation or average, is the central value of a discrete set of numbers: specifically, the sum of the values divided by the number of values."- Wikipedia

3 0
3 years ago
How many times greater is 70 million than 7 million
Dahasolnce [82]

For this case we have the following expressions:

70,000,000

7,000,000

If we divide the first expression by the second we have:

\frac {70,000,000} {7,000,000} = 10

Thus, we have that the first expression is 10 times greater than the second expression.

Answer:

70,000,000 is 10 times greater than 7,000,000

6 0
3 years ago
Is 2/3 greater than 8/12
likoan [24]
2/3 is exactly the same as 8/12
5 0
3 years ago
Read 2 more answers
Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of
tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A                          Sample B

x_A = 30                              x_B = 50

n_A = 100                             n_B =250

Solving (a): Standard error using formula

First, calculate the proportion of A

p_A = \frac{x_A}{n_A}

p_A = \frac{30}{100}

p_A = 0.30

The proportion of B

p_B = \frac{x_B}{n_B}

p_B = \frac{50}{250}

p_B = 0.20

The standard error is:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}

SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}

SE_{p_A-p_B} = \sqrt{0.00274}

SE_{p_A-p_B} = 0.052

Solving (a): Standard error using bootstrapping.

Following the below steps.

  • Open Statkey
  • Under Randomization Hypothesis Tests, select Test for Difference in Proportions
  • Click on Edit data, enter the appropriate data
  • Click on ok to generate samples
  • Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A                          Sample B

x_A = 23                              x_B = 57

n_A = 100                             n_B =250

p_A = 0.230                          p_A = 0.228

So, we have:

SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}

SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}

SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}

SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}

SE_{p_A-p_B} = \sqrt{0.002475064}

SE_{p_A-p_B} = 0.050

5 0
2 years ago
WHATS THE MISSING SIDE PLEASE HURRY IM TIMED
svetoff [14.1K]

Answer: 6.40 = c

Step-by-step explanation:

a^2 + b^2 = c^2

5^2 + 4^2 = c^2

25 + 16 = c^2

41 = c^2

  ____

_/ 41  = c

6.40 = c

4 0
3 years ago
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