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2 years ago

Three rational numbers between 1/3 and 1/5

Mathematics

1 answer:

Gala2k [10]2 years ago

6 0

Three rational numbers between

1/3 and 1/5 are 4/15, 3/10, and 7/30

Given:The two numbers are 1/3 and 1/5

To find:The rational number between two numbers

Solution:Now, to find the rational number, add the numbers and divide their sum by 2.

(i) First rational number between

1/3, 1/5 = 1/3+1/5=8/5

Divide 18/5 by 2------> 8/15 x 1/2= 8/30= 4/15

The series becomes, 1/3, 4/15, 1/5

(ii) Second rational number

= 4/15+1/5 = 7/15

Divide

7/15 by 2 ------> 7/15 x 1/2 = 7/30

Hope this helps!

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tekilochka [14]

Answer: 7/3

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3 years ago

the equation x^3-3x=1 has a solution between 1.8 and 1.9. use a trial and improvement method to find this solution. give your an

Reika [66]

Answer:

The solution to the equation x³ - 3x = 1 is given as :

1.88

Step-by-step explanation:

In the above question, we are given the equation

x³ - 3x = 1 ... Equation 1

and we are told the answer lies between 1.8 - 1.9

Using the trial and improvement method approximating to 2 decimal places

a. First trial we use 1.84 for x in equation 1

1.84³ - 3×1.84 = 0.71

This first trial using 1.84 too small

b. Second trial we use 1.86 for x in equation 1

1.86³ - 3×1.86 = 0.86

This second trial using 1.86 as well is too small

c. For our third trial we use 1.89 for x in equation 1

1.89³ - 3×1.89 = 1.08

This third trial using 1.89 is large. Our target is 1.00

d. Our fourth trial we use 1.88 for x in equation 1

1.88³ - 3×1.88 = 1.004

Approximately to 2 decimal places.

We have = 1.00

Hence the solution to the equation

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Answer:

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On the other hand, if we move our eyes to the left following the curve, this way looking into what values the function adopts for smaller and smaller values of x, we see that the f(x) values decrease (the curve goes down).

Then, to summarize:

a) As we move to the right, thus increasing the values of x, we see the values of f(x) increase

b) As we move to the left, thus decreasing the values of x, we see the values of f(x) decrease.

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