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3 years ago

What is doubled of 13

Mathematics

2 answers:

tekilochka [14]3 years ago

8 0

The answer will be 169 because 13×13=169

Nitella [24]3 years ago

5 0

To double you have to multiply by 2.
13×2=26

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Help please <br><br>number 9, 10

ira [324]

Answer:

#9, G = (-8,-10)

#10, distance = √122 = 11.0453610171

midpoint = (7/2,7/2)

Step-by-step explanation:

#9: We don't need no stinkin' diagrams!!

midpoint M=(-6,-3)

endpoint H=(-4,4)

displacement vector D from H to M:

D = (M-H) = (-6 - -4, -3 - 4) = (-2,-7)

Check: start at endpoint H, move along displacement vector D, should bring you to M.

H + D = (-4,4)+(-2,-7)

= (-4-2,4-7) = (-6,-3) = M ✔

Adding D to endpoint H gets to midpoint M. Adding 2D to H will reach the other endpoint, G.

G = H + 2D = (-4,4)+2×(-2,-7)

= (-4-2×2,4-2×7) = (-8,-10)

Check: Subtracting D from G should bring you back to M.

G-D = (-8,-10) - (-2,-7)

= (-8 - -2, -10 - -7)

= (-6,-3) = M ✔

#10 distance between P and Q, and midpoint of segment PQ:

P=(3,-2) Q=(4,9)

displacement vector D from P to Q:

D = Q - P = (4 - 3, 9 - -2) = (1,11)

so that adding D to P gives Q:

D + P = (1+3,11-2) = (4,9) ✔

Distance between two points is square root of dot product of displacement vector with itself:

d = √(D dot D) = √((1,11)dot(1,11))

= √(1×1+11×11) = √122 = 11.0453610171

Midpoint M is P + D/2, start at P and move half way to Q,

M = (3,-2)+(1,11)/2

= (3+1/2,-2+11/2)

= (7/2,7/2)

Start at M, move D/2 brings you to Q,

M + D/2 = (7/2+7/2) + (1/2,11/2)

= (8/2,18/2) = (4,9) = Q ✔

3 0

3 years ago

Find the equation of the line in slope-intercept form.

ivann1987 [24]

Answer: y= -2x + 7

Step-by-step explanation: Slope intercept form is simply y=mx+b or y= slope(x) + y intercept.

4 0

3 years ago

Read 2 more answers

What notation is used to represent the distance from point A to B

borishaifa [10]

Answer:

Absolute Value

Step-by-step explanation:

Absolute Value is very useful in finding the distance between two points on the number line. The distance between any two points a and b in the number line is

|a-b| or |b-a|.

7 0

2 years ago

Find the domain of goh. g(x) = -x h(x) = 2x²+2x+3

Sedbober [7]

Answer:

not sure

Step-by-step explanation:

6 0

3 years ago

Four buses carrying 146 high school students arrive to Montreal. The buses carry, respectively, 32, 44, 28, and 42 students. One

Naily [24]

Answer:

The expected value of X is $E(X)=\frac{2754}{73} \approx 37.73$ and the variance of X is $Var(X)=\frac{226192}{5329} \approx 42.45$

The expected value of Y is $E(Y)=\frac{73}{2} \approx 36.5$ and the variance of Y is $Var(Y)=\frac{179}{4} \approx 44.75$

Step-by-step explanation:

(a) Let X be a discrete random variable with set of possible values D and probability mass function p(x). The expected value, denoted by E(X) or $\mu_x$ , is

$E(X)=\sum_{x\in D} x\cdot p(x)$

The probability mass function $p_{X}(x)$ of X is given by

$p_{X}(28)=\frac{28}{146} \\\\p_{X}(32)=\frac{32}{146} \\\\p_{X}(42)=\frac{42}{146} \\\\p_{X}(44)=\frac{44}{146}$

Since the bus driver is equally likely to drive any of the 4 buses, the probability mass function $p_{Y}(x)$ of Y is given by

$p_{Y}(28)=p_{Y}(32)=p_{Y}(42)=p_{Y}(44)=\frac{1}{4}$

The expected value of X is

$E(X)=\sum_{x\in [28,32,42,44]} x\cdot p_{X}(x)$

$E(X)=28\cdot \frac{28}{146}+32\cdot \frac{32}{146} +42\cdot \frac{42}{146} +44 \cdot \frac{44}{146}\\\\E(X)=\frac{392}{73}+\frac{512}{73}+\frac{882}{73}+\frac{968}{73}\\\\E(X)=\frac{2754}{73} \approx 37.73$

The expected value of Y is

$E(Y)=\sum_{x\in [28,32,42,44]} x\cdot p_{Y}(x)$

$E(Y)=28\cdot \frac{1}{4}+32\cdot \frac{1}{4} +42\cdot \frac{1}{4} +44 \cdot \frac{1}{4}\\\\E(Y)=146\cdot \frac{1}{4}\\\\E(Y)=\frac{73}{2} \approx 36.5$

(b) Let X have probability mass function p(x) and expected value E(X). Then the variance of X, denoted by V(X), is

$V(X)=\sum_{x\in D} (x-\mu)^2\cdot p(x)=E(X^2)-[E(X)]^2$

The variance of X is

$E(X^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{X}(x)$

$E(X^2)=28^2\cdot \frac{28}{146}+32^2\cdot \frac{32}{146} +42^2\cdot \frac{42}{146} +44^2 \cdot \frac{44}{146}\\\\E(X^2)=\frac{10976}{73}+\frac{16384}{73}+\frac{37044}{73}+\frac{42592}{73}\\\\E(X^2)=\frac{106996}{73}$

$Var(X)=E(X^2)-(E(X))^2\\\\Var(X)=\frac{106996}{73}-(\frac{2754}{73})^2\\\\Var(X)=\frac{106996}{73}-\frac{7584516}{5329}\\\\Var(X)=\frac{7810708}{5329}-\frac{7584516}{5329}\\\\Var(X)=\frac{226192}{5329} \approx 42.45$

The variance of Y is

$E(Y^2)=\sum_{x\in [28,32,42,44]} x^2\cdot p_{Y}(x)$

$E(Y^2)=28^2\cdot \frac{1}{4}+32^2\cdot \frac{1}{4} +42^2\cdot \frac{1}{4} +44^2 \cdot \frac{1}{4}\\\\E(Y^2)=196+256+441+484\\\\E(Y^2)=1377$

$Var(Y)=E(Y^2)-(E(Y))^2\\\\Var(Y)=1377-(\frac{73}{2})^2\\\\Var(Y)=1377-\frac{5329}{4}\\\\Var(Y)=\frac{179}{4} \approx 44.75$

8 0

3 years ago