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sweet [91]
2 years ago
15

A recipe calls for 3 times as many chocolate chips as butterscotch chips. If there are 25 oz of chocolate chips, how many oz do

you need of butterscotch chips. SOLVE USING PROPORTIONAL REASONING
Mathematics
1 answer:
Bingel [31]2 years ago
4 0

The amount, in oz of butterscotch chips needed by proportional reasoning is; 75oz.

<h3>What is the amount of butterscotch chips needed by proportional reasoning?</h3>

It follows from the task content that the the amount of butterscotch chips needed can be determined by means of the proportion premise declared in which case;

  • The recipe requires 3 times as many chocolate chips as butterscotch chips.

Hence, when 25oz of chocolate chips is used, the amount of butterscotch needed is 3 times 25 and hence, = 3 × 25 = 75oz.

Read more on proportion;

brainly.com/question/1496357

#SPJ1

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mr_godi [17]
Area of each side triangle is 1/2*8*15 = 60. There are 5 of them so the triangles have surface area 300. the pentagon's area 1/2*apothegm*sidelength*sides = 1/2*5.5*8*5 = 110. The total area is therefore 300+110 = 410
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3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Fraction means how much from the main graph is it taking, for example, the circle is a 1/4 white 3/4 green to find the decimal, divide the number under the line by the one above it, 4 divided by 3 for example

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