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2 years ago

Find the simple intrest on a 12000 loan with 3.9 intres for 60 mounths

Mathematics

1 answer:

melomori [17]2 years ago

3 0

Answer:

$2,340

Step-by-step explanation:

Simple interest is calculated using the formula: I = prt, where I = simple interest, p = principle amount, r = interest rate and t = time in years. Since the initial, or principle amount is $12,000, the interest rate is 3.9% (0.039) and the time is 60 months, or 5 years (60/12 = 5), we can put these values into the formula and solve for 'I':

I = (12,000)(0.039)(5) = $2,340

You might be interested in

If f(x) = 2х2 +1 and g(x) = х2 -7, find (f-g)(x).

Nookie1986 [14]

Option A

If f(x) = $2x^2 + 1$ and g(x) = $x^2 - 7$ then $(f - g)(x) = x^2 + 8$

Solution:

Given that f(x) = $2x^2 + 1$ and g(x) = $x^2 - 7$

To find: (f - g)(x)

We know that,

(f – g)(x) = f (x) - g(x)

Let us substitute the given values of f(x) and g(x) in above formula,

$(f - g)(x) = 2x^2 + 1 - (x^2 - 7)$

For solving the brackets in above expression,

There are two simple rules to remember:

When you multiply a negative number by a positive number then the product is always negative.

When you multiply two negative numbers or two positive numbers then the product is always positive.

So the expression becomes,

$(f - g)(x) = 2x^2 + 1 -x^2 + 7$

Combining the like terms,

$(f - g)(x) = 2x^2 - x^2 + 1 + 7\\\\(f - g)(x) = x^2 + 8$

Thus option A is correct

8 0

2 years ago

A. 6 B. ⟌50 C. ⟌34 D. 4 Which one?

AfilCa [17]

Answer:

Step-by-step explanation:

3^2 + 5^2 = x^2

9 + 25 = x^2

x^2 = 34

x = sqrt(34)

so the answer is C

6 0

3 years ago

A world record was set for the men’s 100-m dash in the 2008 Olympic Games in Beijing by Usain Bolt of Jamaica. Bolt "coasted" ac

Andrei [34K]

Answer:

a) v = 12.21m/s

a = 4.07 m/s²

b)v = 11.24m/s

a = 3.75 m/s²

Step-by-step explanation:

a) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

v₀ = 0
s₀ = 0
a = ?
v = ?
t = 3s
s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 100

s₀ = x

v = v

t = 9.69 - 3 = 6.69s

s = s₀ + vt

100 = x + v*6.69

100 = x + 6.69v

As x = 3v/2

100 = 3v/2 + 6.69v

100 = 1.5v + 6.69v

100 = 8.19v

v = 12.21m/s

a = v/3 = 4.07 m/s²

b) Dividing the moviment into two parts:

I - With acceleration

v = v₀ + at

s = s₀ + v₀t + at²/2

v₀ = 0
s₀ = 0
a = ?
v = ?
t = 3s
s = x

v = v₀ + at

v = 3a ⇒ a = v/3

s = s₀ + v₀t + at²/2

x = v/3.3²/2

x = 3v/2

II - Uniform

s = s₀ + vt

s = 200

s₀ = x

v = v

t = 19.30 - 3 = 16.30s

s = s₀ + vt

200 = x + v*16.3

100 = x + 16.3v

As x = 3v/2

200 = 3v/2 + 16.3v

200 = 1.5v + 16.3v

200 = 17.8v

v = 11.24m/s

a = v/3 = 3.75 m/s²

8 0

2 years ago

Show work please \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$