The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
C!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
6
Step-by-step explanation:
There are 2 significant figures (sig figs) which are the two '5' digits. The zeros aren't considered sig figs because we can write the number as 5.5 * 10^8 to represent the exact same idea. The 0's are simply placeholders to tell how big the number is, not necessarily how accurate it is. If the 0s were between the decimal point and a nonzero value, then the 0s would be significant. If the 0s were to the right of the decimal, then they would be significant.
Answer: 2
Answer:
The answer is C (6.21).
Step-by-step explanation:
