Answer:
Aqueous carbon dioxide, CO2 (aq), reacts with water forming carbonic acid, H2CO3 (aq). Carbonic acid may loose protons to form bicarbonate, HCO3- , and carbonate, CO32-. In this case the proton is liberated to the water, decreasing pH. The complex chemical equilibria are described using two acid equilibrium equations.
PLS MARK AS BRAINLIEST
Solution:
The process of transaction can guarantee the reliability of business applications. Locking resources is widely used in distributed transaction management (e.g; two phase commit, 2PC) to keep the system consistent. The locking mechanism, however, potentially results in various deadlocks. In service oriented architecture, the deadlock problem becomes even worse because multiple transactions try to lock shared resources in the unexpectable way due to the more randomicity of transaction requests, which has not been solved by existing research results. In this paper, we investigate how to prevent local deadlocks, caused by the resource competition among multiple sub-transactions of a gl obal transaction, and global deadlocks from the competition among different global transactions. We propose a replication based approach to avoid the local deadlocks, and a timestamp based approach to significantly mitigate the global deadlocks. A general algorithm is designed for both local and global deadlock prevention. The experimental results demonstrate the effectiveness and efficiency of our deadlock prevention approach. Further, it is also proved that our approach provides higher system performance than traditional resource allocation schemes.
This is the required answer.
Open this occurence and open the series is the two options to choose from, from the dialog box that shows when attempting to modify the appointments
Answer:
#include <stdio.h>
typedef struct TimeHrMin_struct //struct
{
int hours;
int minutes;
} TimeHrMin;
struct TimeHrMin_struct SetTime(int hoursVal,int minutesVal) //SetTime function
{
struct TimeHrMin_struct str;
str.hours=hoursVal; //assigning the values
str.minutes=minutesVal;
return str; //returning the struct
}
int main(void)
{
TimeHrMin studentLateness;
int hours;
int minutes;
scanf("%d %d", &hours, &minutes);
studentLateness = SetTime(hours, minutes); //calling the function
printf("The student is %d hours and %d minutes late.\n", studentLateness.hours, studentLateness.minutes);
return 0;
}
Explanation:
5x2 =69
Explication but brain
