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nydimaria [60]
3 years ago
9

2. The password dilemma refers to the fact that: A. Passwords that are easy for users to remember are also easy for attackers to

guess. B. The more difficult we make it for attackers to guess our passwords, and the more frequently we force password changes, the more difficult the passwords are for authorized users to remember and the more likely they are to write them down. C. Users will invariably attempt to select passwords that are words they can remember. This means they may select things closely associated with them, such as their spouse’s or child’s name, a beloved sports team, or a favorite model of car. D. Passwords assigned by administrators are usually better and more secure, but are often harder for users to remember.
Computers and Technology
1 answer:
Sholpan [36]3 years ago
5 0

Answer:

Option A.

Explanation:

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Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
You’re mapping out the logical relations of a database, and you notice that one of your tables will have a pair of child records
Jet001 [13]
The answer to your question is answer A
3 0
3 years ago
You can add additional design elements to a picture by adding a color background, which is accomplished by using what Paint feat
katrin2010 [14]

Answer:

Fill with Color tool

6 0
3 years ago
CPT (Current Procedural Terminology) codes consist of 3-4 numbers representing a unique service. True False
xz_007 [3.2K]
This is in fact false to my knowledge
4 0
3 years ago
. In Laissez-faire Styleof Group Leadership, Members of the group are not given help inactivity plans by the leader only when it
Trava [24]

Answer:

The statement is false.

Explanation:

In Laissez-faire Style of group leadership, the members of the group are given all the responsibilities by the leader or the manager. The members of the group take all the decisions and control the working of the group. The manager provides with some guidance or support only when it is asked by the group members.

4 0
3 years ago
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